## Recent Questions

1 views

### Equations Y1 = A\sin \omega T And Y2 = \frac{A}{2}\sin \omega T + \frac{A}{2}\cos \omega T Represent S.H.M. The Ratio Of The Amplitudes Of The Two Motions Is

JEE Discussions

Modified 0 Days 0 Hour 0 Minutes Ago Sophie

1 views

### A S.H.M. Is Represented By The Equation Y = 10 Sin 20pt. Its Frequency Is

JEE Discussions

Modified 0 Days 0 Hour 4 Minutes Ago Christopher

2 views

### The Displacement Y Of A Particle Executing Periodic Motion Is Given By Y = 4\cos ^2 (t/2)\sin (1000\,t) . This Expression May Be Considered To Be A Result Of The Superposition Of Independent Harmonic

JEE Discussions

Modified 0 Days 0 Hour 6 Minutes Ago Stewart

1 views

### The S.H.M. Of A Particle Is Given By The Equation Y = 3\sin \omega \,t + 4\cos \omega \,t . The Amplitude Is

JEE Discussions

Modified 0 Days 0 Hour 8 Minutes Ago Richard

1 views

### A Particle Is Performing Simple Harmonic Motion Along X-axis With Amplitude 4 Cm And The Period 1.2 Sec. The Minimum Time Taken By The Particle To Move From X = 2 Cm To X = +4 Cm And Back Again Is Giv

JEE Discussions

Modified 0 Days 0 Hour 12 Minutes Ago Charles

2 views

### Two Particles Executes S.H.M. Of Same Amplitude And Frequency Along The Same Straight Line. They Pass One Another When Going In Opposite Directions, Each Time Their Displacement Is Half Of Their Ampli

JEE Discussions

Modified 0 Days 0 Hour 23 Minutes Ago Molly

5 views

### A Particle Is Executing Simple Harmonic Motion With A Period Of T Seconds And Amplitude A Metre. The Shortest Time To Reach A Point A/root2 M From Its Mean Position In Seconds Is

JEE Discussions

Modified 0 Days 0 Hour 42 Minutes Ago Victoria

3 views

### The Equation Of S.H.M. Is Y = Asin (2 Root Nt + A), Then Its Phase At Time T Is

JEE Discussions

Modified 0 Days 0 Hour 47 Minutes Ago Pooja

1 views

### A Particle Executes Simple Harmonic Motion Between X=-A And X=+A. The Taken For It To Go From 0 To A/2 Is T1 And To Go From A/2 To A Is T2. Then

JEE Discussions

Modified 0 Days 0 Hour 50 Minutes Ago Rose

3 views

### The Equation Of A Simple Harmonic Motion Is X=0.34 Cos (3000t + 0.74) Where X And T Are In Mm And S. The Frequency Of Mostion Is

JEE Discussions

Modified 0 Days 0 Hour 55 Minutes Ago Carolyn

2 views

### A Particle Executing S.H.M. Of Amplitude 4 Cm And T = 4 Sec. The Time Taken By It To Move From Positive Extreme Position To Half The Amplitude Is

JEE Discussions

Modified 0 Days 1 Hour 20 Minutes Ago Victoria

3 views

### Two Particle Executes S.H.M. Of Some Amplitude And Frequency Alone The Same Straight Line. They Pass One Another When Going In Opposite Direction Each Time Their Displacement Is Half Of Theidifference

JEE Discussions

Modified 0 Days 1 Hour 26 Minutes Ago Bella

1 views

### A Particle Is Executing Simple Harmonic Motion With A Period Of T Seconds And Amplitude A Meter. The Shortest Time It Takes To A Point A/root2 M Form Its Mean Its Mean Position In Seconds Is

JEE Discussions

Modified 0 Days 1 Hour 34 Minutes Ago Sophie

1 views

### The Equation Of S.H.M. Is Y = Asin (2root Nt + A), Then Its Phase At Time T Is

JEE Discussions

Modified 0 Days 1 Hour 42 Minutes Ago Alexandra

1 views

### A Particle Executes Simple Harmonic Motion Between X=-A And X=+A. The Taken For It To Go From 0 To A/2 Is T1 And To Go Form A/2 To A Is T2. Then

JEE Discussions

Modified 0 Days 1 Hour 47 Minutes Ago Sonia

7 views

### A Particle Starts S.H.M. From The Mean Position. Its Amplitude Is A And Time Period Is T. At The Time When Its Speed Is Half Of The Maximum

JEE Discussions

Modified 0 Days 4 Hour 40 Minutes Ago Chahat Ali

11 views

### Need To Write SAT 2 To Get Admission In NIT - Wrote JEE In January With Residence VISA Of Dubai

COLLEGE & UNIVERSITIES Discussions

Modified 1 Days 4 Hour 16 Minutes Ago Rokith Rajan

12 views

### |1 5 Pi | Log E 5 Root 5| |log10^10 5 E| =

JEE Discussions

Modified 7 Days 0 Hour 21 Minutes Ago Thomas

3 views

### Delta = | A A+b A+b+c| |3a 4a+3b 5a+4b+3c| |6a 9a+6b 11a+9b+6c| Where

JEE Discussions

Modified 7 Days 0 Hour 23 Minutes Ago Julian

7 views

### If Omega Be A Complex Cube Root Of Unity, Then

JEE Discussions

Modified 7 Days 0 Hour 25 Minutes Ago Rachel

4 views

### If |y+z X Y| |z + X Z X| |x+y Y Z| = K(x+y+z)(x-z)^2, Then K =

JEE Discussions

Modified 7 Days 0 Hour 26 Minutes Ago Rebecca

7 views

### |b^2 -ab B-c Bc-ac| |ab-a^2 A-b B^2 - Ab| |bc - Ac C - A Ab - A^2| =

JEE Discussions

Modified 7 Days 0 Hour 29 Minutes Ago Stephen

4 views

### If Alpha, Beta Are The Roots Of The Equation 2x^2 + 3x + 5 = 0, Then The Value Of The Determinant

JEE Discussions

Modified 7 Days 0 Hour 32 Minutes Ago Joan

7 views

### If |1+a 1 1| |1 1+b 1| |1 1 1+c| = 0. Then The Value Of

JEE Discussions

Modified 7 Days 0 Hour 34 Minutes Ago Peter

7 views

### |a^2 B^2 C^2| |(a+1)^2 (b+1)^2 (c+1)^2| |(a-1)^2 (b-1)^2 (c-1)^2| =

JEE Discussions

Modified 7 Days 0 Hour 38 Minutes Ago Diana

5 views

### If Omega Is An Imaginary Root Of Unity, Then The Value Of

JEE Discussions

Modified 7 Days 0 Hour 41 Minutes Ago Boris

6 views

### The Values Of X For Which The Following Determinant Equation,

JEE Discussions

Modified 7 Days 0 Hour 42 Minutes Ago Amy

8 views

### |b+c A A| | B C+a B| |c C A+b| =

JEE Discussions

Modified 7 Days 0 Hour 43 Minutes Ago Pranav

6 views

### If Omega Is The Cube Root Of Unity, Then

JEE Discussions

Modified 7 Days 0 Hour 47 Minutes Ago Lisa

3 views

### If |-a^2 Ab Ac| |ab -b^2 Bc| |ac Bc -c^2| = Ka^2b^2c^2, Then K =

JEE Discussions

Modified 7 Days 0 Hour 48 Minutes Ago Grace