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The S.H.M. Of A Particle Is Given By The Equation Y = 3\sin \omega \,t + 4\cos \omega \,t . The Amplitude Is
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A Particle Executes Simple Harmonic Motion Between X=A And X=+A. The Taken For It To Go From 0 To A/2 Is T1 And To Go From A/2 To A Is T2. Then
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The Equation Of A Simple Harmonic Motion Is X=0.34 Cos (3000t + 0.74) Where X And T Are In Mm And S. The Frequency Of Mostion Is
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A Particle Executes Simple Harmonic Motion Between X=A And X=+A. The Taken For It To Go From 0 To A/2 Is T1 And To Go Form A/2 To A Is T2. Then
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A Particle Starts S.H.M. From The Mean Position. Its Amplitude Is A And Time Period Is T. At The Time When Its Speed Is Half Of The Maximum
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Need To Write SAT 2 To Get Admission In NIT  Wrote JEE In January With Residence VISA Of Dubai
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1 5 Pi  Log E 5 Root 5 log10^10 5 E =
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If Omega Be A Complex Cube Root Of Unity, Then
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If y+z X Y z + X Z X x+y Y Z = K(x+y+z)(xz)^2, Then K =
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If Alpha, Beta Are The Roots Of The Equation 2x^2 + 3x + 5 = 0, Then The Value Of The Determinant
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If 1+a 1 1 1 1+b 1 1 1 1+c = 0. Then The Value Of
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If Omega Is An Imaginary Root Of Unity, Then The Value Of
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The Values Of X For Which The Following Determinant Equation,
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b+c A A  B C+a B c C A+b =
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If Omega Is The Cube Root Of Unity, Then
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If a^2 Ab Ac ab b^2 Bc ac Bc c^2 = Ka^2b^2c^2, Then K =
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