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LimX-->0 1-cosMX/1-cosNX =
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The Value Of LimX-->1 Sin(e^x-1 -1)/logX Is
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The Value Of The Limit LimX-->2 E^3x-6 -1/sin(2-x) Is
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The Value Of LimX-->infinity RootX+rootX+rootX....+rootX Is
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Lim Theta-->0 4theta(4theta-sin Theta)/(1-cos2theta)^2 Is
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The Value Of The Constant Alpha And Beta Such That LimX-->infinity (x^2+1/x+1 -alphaX-beta)=0 Are Respectively
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Lim X-->pie/2 CotX-cosX/(pie-2x)^3 Equal
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The Value Of Lim X-->0 (4^x-1)^3/sin X^2/4 Log (1+3x), Is
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The Value Of Lim X-->0 1+sinX-cosX+log(1-x)/x^3, Is
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Lim X-->0 E^ax-e^beta X/x =
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The Value Of Lim N-->infinity 1/1.3+1/3.5+1/5.7+1/7.9+...+1/(2n-1)(2n+1) Is Equal To
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Lim X-->0 E^1/x/e(1/x+1)=
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Lim X-->4[x^3/2 -8/x-4]=
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Lim X-->0 (cos Ex X )^1/logX Equal
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Lim X-->0 X Log Sin X Is Equal To
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Lim X-->0 E^tanX -e^x/tanX-x =
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Lim X-->0 Sin(1/x) Is
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The Value Of Lim X-->0 (1+x)^1/x -e+1/2 Ex/x^2 Is
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Lim X-->0 |x|/x=
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The Value Of Lim N-->infinity 1-n^2/sum N Will Be
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Scholarship After DASA - Documents Needed For DASA Application - Where To Submit DASA Application
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The Value Of Lim A-->0 Sin A - Tan A/sin^3 A Will Be
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Let F:R-->R Be A Differentiable Function Having F(2)=6, F(2)=(1/48). Then Lim X -->2 F(x) Integral 6 4t^3/x-2 Dt Equals
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Range Of F(x)=[x]-x Is
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The Interval For Which Sin^-1 Rootx+cos^-1 Rootx=pie/2 Holds
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The Interval For Which Sin^-1 Root X+cos^-1 Root X=Ï€/2 Holds
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The Function F(x)=sec^-1x/root X-[x], Where [.] Denotes The Greatest Integer Less Than Or Equal To X Is Defined For All X Belonging To
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