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Popular Questions
- the value of limX-->infinity x^2sin1/x-x/1-|x| is
- limX-->0 [sin(x+a)+sin(a-x)-2sina/XsinX]=
- the value of limX-->0 root1-cosX^2/1-cosX is
- limX-->pie/2 {(1-sinX)tanX} is
- the value of limX-->a log(x-a)/log(e^x -e^a) is
- the value of limN-->infinity cos(x/2)cos(x/4)cos(x/8)....cos(x/2^n) is
- the value of limX-->2 3^x/2 -3/3^x-9 is
- it is given that f(a) exists, then lim x-->a xf(a)-a f(x)/x-a is equal to
- the value of limX-->1 sin(e^x-1 -1)/logX is
- lim x-->pie/2 cotX-cosX/(pie-2x)^3 equal
- the value of the limit limX-->2 e^3x-6 -1/sin(2-x) is
- lim x-->0 sin(1/x) is
- the value of limX-->7 2- root x-3/x^2 -49 is
- lim x-->0 (cos ex x )^1/logX equal
- limX-->0 sin^-1x-tan^-1x/x^3 is equal to
- limX-->0 sin(2+x)-sin(2-x)/x =
- the value of limX-->2 3^x/2 -3/3^x -9 is
- the value of lim a-->0 sin a - tan a/sin^3 a will be
- lim theta-->0 4theta(4theta-sin theta)/(1-cos2theta)^2 is
- limX-->1 tan(x^2-1)/x-1 is equal to
- if a1=1 and a n+1 = 4+3an/3+2an, n greater then equal to 1 and if limN-->infinity a n =n, then the value of a is
- the value of lomX-->0+ x m (logX)n, m,nE N is
- the value of lim N-->infinity 1-n^2/sum n will be
- LimX-->pie/2 [xtanX-(pie/2) secX]=
- limX-->-1 root pie - root cos^-1 x/root x+1 is given by
- the value of limX-->0(a^x+b^x+c^x/3)^2/x ; (a,b,c>0) is
- f(x)=x+|x| is continuous for
- limX-->0[1/x - log(1+x)/x^2]=
- limX-->2 |x-2|/x-2 =
- limX-->0 e^x^2 - cosX/x^2 =
- limN-->infinity [1/n^3+1 + 4/n^3+1 + 9/n^3+1 +........+ n^2/n^3+1]=
- if sn = the súm from k equal 1 to n ak and limN-->infinity an = a, then lim n-->infinity sN+1-sn/root the súm from k equal 1..
- limX-->a cosX-cosA/cotX-cotA =
- limX-->0 x/|x|+x^2 =
- if f(R)= pieR^2, then limH-->0 f(r+h)-f(r)/h=
- limX-->infinity (X+1)^10+(x+2)^10+.....+(X+100)^10/x^10+10^10 is equal to
- the value of limX-->infinity rootX+rootX+rootX....+rootX is
- the value of limX-->0 xcosX-log(1+x)/x^2 is
- Let f:R-R be the positive increasing function
- f(x)={2x, x<0 , 2x+1, x greater than equal to 0. then
