NEET Discussions - The Boiling Point Of Water (100°C) Becomes 100.52°C, If 3 Grams Of A Non-volatile Solute Is Dissolved In 200 Ml Of Water. The Molecular Weight Of Solute Is (if Kb For Water Is = 0.6 K/m)

The Boiling Point Of Water (100°C) Becomes 100.52°C, If 3 Grams Of A Non-volatile Solute Is Dissolved In 200 Ml Of Water. The Molecular Weight Of Solute Is (if Kb For Water Is = 0.6 K/m)

Bhushan Mudliyar 4 Years Ago

The boiling point of water (100°C) becomes 100.52°C, if 3 grams of a non-volatile solute is dissolved

in 200 ml of water. The molecular weight of solute is (if K_b for water is = 0.6 K/m)

(1) 17.3g.moI^- 1 (2) 15.4g.moI^- 1 (3) 12.2g.moI^- 1 (4) 20.4g.moI^- 1

asked Jun 14 12:00:00 AM

Q: 537 A: 0