NEET Discussions - At 80°C, The Vapor Pressure Of Pure Liquid A Is 520 MmHg And That Of Pure Liquid B Is 1000 Mm Hg. If A Mixture Solution A And B Boils At 80°C And 1 Atm Pressure, The Amount Of A In The Mixture Is (1 Atm = 760 MmHg)

At 80°C, The Vapor Pressure Of Pure Liquid A Is 520 MmHg And That Of Pure Liquid B Is 1000 Mm Hg. If A Mixture Solution A And B Boils At 80°C And 1 Atm Pressure, The Amount Of A In The Mixture Is (1 Atm = 760 MmHg)

Bhushan Mudliyar 4 Years Ago

119

At 80°C, the vapor pressure of pure liquid A is 520 mmHg and that of pure liquid B is 1000 mm

Hg. If a mixture solution A and B boils at 80°C and 1 atm pressure, the amount of A in the

mixture is (1 atm = 760 mmHg)

(1) 52 mole per cent

(2) 34 mole per cent

(3) 48 mole per cent

(4) 50 mole per cent

asked Jun 14 12:00:00 AM

Q: 537 A: 0