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LimX-->0 Sin^-1x-tan^-1x/x^3 Is Equal To
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The Value Of LimX-->0 XcosX-log(1+x)/x^2 Is
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LimN-->infinity 1/2+1/2^2+1/2^3+....+1/2^n Equals
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LimX-->0(a^x-b^x/x) =
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LimX-->a (x+2)^5/3 -(a+2)^5/3/x-a =
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The Value Of LimX-->0 27^x-9^x-3^x+1/root 5-root 4+cosX Is
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The Value Of LimX-->infinity X^n/x^n+1 Where X<-1 Is
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The Value Of LimX-->infinity (x+1)(3x+4)/x^2(x-8) Is Equal To
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LimX-->infinity [1+ 1/mx]^x Equal To
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LimX-->1 X^m-1/x^n-1=
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The Value Of LimX-->0 Log[1+x^3]/sin^3X =
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LimN-->infinity [sumN^2/n^3]=
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LimN-->infinity (n/n+y)^n Equals
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Lim X-->0 X.2^x-x/1-cosX =
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LimX-->infinity 3.2^n+1-4.5^n+1/5.2^n+7.5^n=
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LimX-->1 Tan(x^2-1)/x-1 Is Equal To
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0 votes0 answer127 views
The Value Of HimX-->0 5^x-5^-x/2x=
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LimX-->0(1-ax)^1/x=
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LimX-->0 A^sinX-1/b^sinX-1=
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LimX-->1 1+logX-x/1-2x+x^2=
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If F(x)={sinX,x,is Not Equal To N Pie, NEZ 0, Otherwise And G(x)={x^2+1,x Is Not Equal To 0, 2 4,x=0 5,x=2 Then LimX-->0 G(f(x)}=
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LimX-->0 (1+x)^n-1/x=
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LimN-->infinity [1^3+2^3+3^3+.......+n^3/n^4]=
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LimX-->0 (1+tanX/1+sinX)^cosecX Is Equal To
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LimX-->0 1-cosMX/1-cosNX =
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The Value Of LimX-->1 Sin(e^x-1 -1)/logX Is
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The Value Of The Limit LimX-->2 E^3x-6 -1/sin(2-x) Is
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The Value Of LimX-->infinity RootX+rootX+rootX....+rootX Is
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Lim Theta-->0 4theta(4theta-sin Theta)/(1-cos2theta)^2 Is
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The Value Of The Constant Alpha And Beta Such That LimX-->infinity (x^2+1/x+1 -alphaX-beta)=0 Are Respectively
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