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LimH-->0 2[root3 Sin(pie/6+h)-cos(pie/6+h)]/root3h(3cosH-sinH)
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Lim Theta-->0 5theta Cos Theta-2sin Theta/3theta+tan Theta =
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The Value Of LimX-->0 E^x+log(1+x)-(1-x)^-2/x^2 Is Equal To
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If A,b,c,d Are Positive, Then LimX-->infinity (1+1/a+bx)^c+dx =
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