Recent Questions
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In Triangle ABC ,G Is The Centroid, D Is The Mid-point Of BC. If A = ( 2,3 ) And G = ( 7,5 ), Then The Point D Is
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The Vertices P, Q And R Of A Triangle Are (2, 1) , (5, 2) And (3, 4), Respectively. Then, The Circumcentre Is
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The Coordinates Of The Orthocentre Of The Triangle Formed By (0, 0) , (8, 0) And (4, 6) Is
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Modified 4 Year Ago
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The Coordinates Of The Incentre Of The Triangle Having Sides 3x - 4y = 0, 5x + 12y = 0 And Y - 15 = 0 Are
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The Vertices Of A Triangle Are (6, 0), (0, 6) And (6, 6). The Distance Between Its Circumcentre And Centroid Is
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0 votes1 answer119 views
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Modified 4 Year Ago
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The Vertices Of A Triangle Are A (0, 0), B (0, 2) And C (2, 0), Then Find The Distance Between Its Orthocentre And Circumcentre
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0 votes1 answer215 views
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The Circumcentre Of The Triangle With Vertices (8, 6), (8, - 2) And (2, - 2) Is At The Point
JEE DiscussionsModified 4 Year Ago
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0 votes1 answer119 views
The Ratio In Which The Line X + Y = 4 Divides The Line Joining The Points (1, - 1) And (5, 7) Is
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0 votes1 answer385 views
Points (1/2, - (13/4)) Divides The Line Joining The Points (3, - 5) And (-7, 2) In The Ratio Of
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(0, - 1) And (0, 3) Are Two Opposite Vertices Of A Square. The Other Two Vertices Are
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The Mid - Points Of The Sides Of A Triangle Are D (6, 1), E (3, 5) And F(-1, - 2), Then The Vertex Opposite To D Is
JEE DiscussionsModified 4 Year Ago
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0 votes1 answer135 views
The Point P Is Equidistant From A (1, 3), B (-3, 5) And C (5, -1), Then PA Is Equal To
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0 votes1 answer126 views
If P(1, 2), Q (4, 6), R(5, 7) And S (a, B) Are The Vertices Of A Parallelogram PQRS, Then
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The Image Of The Center Of The Circles X^2 + Y^2 = A^2 With Respect To The Mirror Image X + Y = 1 Is
JEE DiscussionsModified 4 Year Ago
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The Mid Point Of The Line Joining The Points (-10, 8) And (-6, 12) Divides The Line Joining The Points (4, - 2) And (-2, 4) In The Ratio
JEE DiscussionsModified 4 Year Ago
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0 votes1 answer205 views
Ne Possible Condition For The Three Points (a, B), (b, A) And (a^2, - B^2) To Be Collinear, Is
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0 votes1 answer216 views
Point Q Is Symmetric To P(4, - 1) With Respect To The Bisector Of The First Quadrant. The Length Of PQ Is
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0 votes1 answer197 views
If A (k,2) And B (3, 5) Are Points C(1, 1) Divides AB From A Is In The Ratio Of K, That K
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If C Is The Reflection Of A(2, 4) In X - Axis And B Is The Reflection Of C Is Y - Axis, Then |AB| Is Equal To
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If Algebraic Sum Of Distances Of A Variable Line From Points (2, 0), (0, 2) And (-2, -2) Is Zero, Then The Line Passes Through The Fixed Point
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