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There Is A Staircase As Shown In Figure Connecting Points A And B. Measurements Of Steps
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In Triangle ABC, Angle C Is An Obtuse Angle, AD Perpendicular BC
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Triangle ABC Is A Right Triangle In Which Angle C = 90 Degree
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Find The Altitude Of An Equilateral Triangle Of Side 8 Cm
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In The Given Figure, If CD = 17 M, BD = 8 M And AD = 4 M
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If The Lengths Of The Diagonals Of Rhombus Are 16 Cm And 12 Cm
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In The Given Figure, Angle B < 90 Degree And Segment
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AD Is An Altitude Of An Equilateral Triangle ABC. On AD As Base Another Equilateral
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Two Isosceles Triangles Have Equal Vertical Angles And Their Areas
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If The Areas Of Two Similar Triangles Are 81 Cm Square And 49 Cm Square Respectively
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In The Given Figure, DE || BC, DE = 4 Cm, BC = 8 Cm
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In The Given Figure, S And T Are Points On The Sides PQ And PR Respectively Of Triangle PQR, Such That PT = 2
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Triangle ABC And Triangle DEF Are Similar And AB = 1/3 DE, Then Find
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Prove That The Line Segment Joining The Mid-points Of The Sides Of A Triangle From Four
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