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A Horizontal Overhead Power Line Is At A Height Of 4m From The Ground And Carries A Current Of 100 A From East To West
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A Current I Ampere Flows In A Circular Arc Of Wire Whose Radius Is R
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A Steady Current I Goes Through A Wire Loop PQR Having Shape Of A Right Angle Triangle With PQ = 3x, PR = 4x And QR = 5x
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The Magnetic Field DB Due To A Small Current Element Dl At A Distance R And Element Carrying Current I Is
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If A Long Hollow Copper Pipe Carries A Direct Current, The Magnetic Field Associated With The Current Will Be
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An Equilateral Triangle Is Made By Uniform Wires AB, BC, CA. A Current I Entres At A And Leaves From The Mid Point BC
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A Current Loop In A Magnetic Field
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The Magnetic Induction At A Point P Which Is At A Distance 4cm From A Long Current Carrying Wire Is
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A Long Straight Wire Of Radius A Carries A Steady Current I. The Current Is Uniformly Distributed Over Its Cross-section
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In Using Amperes Law To Find The Magnetic Field Of A Straight, Long Solenoid, The Loop (Amperian) That Is Taken Is
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A Horizontal Overhead Power Line Is At A Height Of 4m From The Ground And Carries A Current Of 100 A From East To West
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A Steady Current I Goes Through A Wire Loop PQR Having Shape Of A Right Angle Triangle With PQ = 3x, PR = 4x And QR =5x.
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