The Locus Of The Centre Of A Circle, Which Touches Externally The Circle X^2 + Y^2 - 6x - 6y + 14 = 0 And Also Touches The Y-axis, Is Given By The Equation:

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3 Years Ago

1 Answers

  • tpkimgansCorrect Answer D

    3 Years Ago

    asked May 07 12:00:00 AM

    Q: 9 A: 1

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