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Popular Questions
- Thw quadratic equation whose roots are three times the roots of
- Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equation
- If alpha, beta are the roots of x^2 - ax + b = 0 and if
- aum of roots is -1 and sum of their reciprocals is 1/6, then equation is
- Let for
- The equation
- If Sin A, Sin B, Cos A are in G.P., then roots of
- Let
- If the
- The number which exceeds its positive square root by 12 is
- If the roots of the given equation (m^2 +1)x^2 + 2amx + a^2 - b^2 = 0 be equal, then
- If | x -2 | + | x - 3 |= 7, then x =
- All the values of m for which both roots of the equation
- If alpha, beta are the roots of the equation
- The number of real roots of the equation
- If p,q,r are real and p not equal to q, then the roots of the equation
- The roots of the equation
- If alpha and beta are the roots of the equation
- If a and b are the odd integers, then the roots of the equation
- The number of the roots of the quadratic equation
- The equation whose roots are
- The values of a for which 2x^2 - 2(2a + 1) x + a(a + 1) = 0 may have one root less than a and other root greater than a are given ..
- The value of m for which the equation
- The number of real roots of the equation
- If the sum of the roots of the equation
- The value of
- The number of solutions of
- The suk of the fourth powers of the roots of the equation
- The sum of the roots of a equation is 2 and sum of their cubes is 98, then the equation is
- If the roots of 4x^2 + 5k = (5k +1)x differ by unity, then the negative value of k is
- A real root of the equation log4
- The equation formed by decreasing each root of
- For what value of k will the equation
- The value of k for which the equation
- If the roots of the quadratic equation x-m/mx+1 = x+n/ nx +1 are reciprocal to each other, then
- If the roots of equation x^2 + a^2 = 8x + 6a are real, then
- If the roots of the equation x^2 - 5x + 16 = 0 are alpha, beta and the roots of equation
- If ax^2 + bx + c = 0, then x =
- The solution set of the equation pqx^2 - (p+q)^2 x + (p+q)^2 = 0 is
- If alpha, beta are the roots of the equation 6x^2 - 5x + 1 = 0. then
