We Express [(cos2 Theetha - I Sin 2 Theetha)^4 ( Cos4 Theetha+i Sin 4 Theetha)^-5]/ [(cos3 Theetha+ I Sin3 Theetha)^-2 ( Cos3 Theetha - I Sin3 Theetha)^-9 In The For Of X + Iy We Get

Previous   /   Next
4 Years Ago

0 Answers

Your Answer

Connect With Answers

We are available 24x7 to answer.



+ =


Notification

Your post is submitted for moderation. It will be updated soon.