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4 Years Ago

If The Kinetic Energy Of A Body Is Increased Two Times, Its Momentum Will

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Two Balls Of Masses 2 G And 6 G Are Moving With Kinetic Energy In The Ratio Of 3 : 1. What Is The Ratio Of Their Linear Momenta?

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A Body Of Mass 5 Kg Is Thrown Vertically Up With A Kinetic Energy Of 490 J. The Height At Which The Kinetic Energy Of The Body Becomes Half Of The Original Value Is

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Two Bodies Of Masses M1 And M2 Are Acted Upon By Constant Force F For A Time T. They Start From Rest And Acquire Kinetic Energies E1 And E2, Respectively. Then, E1/E2 Is

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Potential Energy Of A Particle Is To Î± Coordinate By Equation X^2 - 2x Will Be Equilibrium At

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4 Years Ago

A Particle Of Mass 4m Which Is At Rest Explodes Into Three Fragments. Two Of The Fragments Each Of Mass M Are Found To Move With A Speed V Each Mutually Perpendicular Directions. The Total Energy Rele

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4 Years Ago

The Magnitude Of Momentum Of Particle Is Increased By 100%. The Increase In Its Kinetic Energy Is

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4 Years Ago

A Particle Which Is Constrained To Move Along The X-axis, Is Subjected To A Force In The Same Direction Which Varies With The Distance X Of The Particle From The Origin Is F (x) = - Kx + Ax^3 . Here K

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Modified 4 Year Ago
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4 Years Ago

A Spring Of Force Constant 800 Nm^-1 Has An Extension Of 5cm. The Work Done In Extending It From 5 Cm To 15 Cm Is

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4 Years Ago

A Bullet Of Mass 10 G Is Fired Horizontally With A Velocity 1000 Ms^-1 From A Rifle Situated At A Height 50 M Above The Ground. If The Bullet Reaches The Ground With A Velocity 500 Ms^-1, The Work Don

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4 Years Ago

If W1, W2, And W3 Represent The Work Done In Moving A Particle From A To B Along Three Different Different Paths 1,2 And 3 Respectively (as Show )in The Gravitational Field Of A Point Mass M, Find The

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4 Years Ago

An Ideal Spring With Spring-constant K Is Hung From The Ceiling And A Block Of Mass M Is Attached To Its Lower End. The Mass Is Released With The Spring Initially Unstretched. Then The Maximum

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4 Years Ago

A Particle Of Mass 100 G Is Thrown Vertically Upwards With A Speed Of 5 Ms^-1. The Work Done By The Force Of Gravity During The Time, The Particle Goes Up Is

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4 Years Ago

A Mass Of M Kg Is Suspended By A Weightless String. The Horizontal Force That Is Required To Displace It Until The String Makes An Angle Of 45Â° With The Initial Vertical Direction Is

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4 Years Ago

A Body Moves A Distance Of 10 M Along A Straight Line Under A Action Of 5 N Force. If Work Done Is 25 J, Then Angle Between The Force And Direction Of Motion Of The Body Will Be

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4 Years Ago

When A Spring Is Stretched By A Distance X It Experts A Force Given By F (- 5x - 16x^3) N The Work Done When The Spring Stretched From 0.1 M To Done When The Spring Is Stretched From

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4 Years Ago

4 M^3 Of Water Is To Be Pumped To A Height Of 20 M And Forced Into A Reservoir At A Pressure Of 2 X 10^5 Nm^-2. The Work Done By The Motor Is (given, External Pressure =10^5 Nm^-2)

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Modified 4 Year Ago
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4 Years Ago

A Tennis Ball Is Dropped On A Horizontal Smooth Surface. It Bounces Back To Its Original Position After Hitting The Surface. The Force On The Ball During The Collision Is Proportional To The Length Of

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4 Years Ago

A Tennis Ball Is Dropped On A Horizontal Smooth Surface. It Bounces Back To Its Original Position After Hitting The Surface. The Force On The Ball During The Collision Is Proportional To The Length Of

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Modified 4 Year Ago
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4 Years Ago

The Work Done By A Force Acting On A Body Is As Shown In The Graph. The Total Work Done In Covering An Initial Distance Of 20 M Is

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4 Years Ago

A Spring Of Force-constant K Is Cut Into Two Pieces Such That One Piece Is Double The Length Of The Other. Then The Long Piece Will Have A Force-constant Of

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4 Years Ago

If W1, W2 And W3 Are The Work Done In Moving A Particle From A And B Along Three Different Paths 1, 2 And 3 Respectively (as Shown) In The Gravitational Field Of A Point Mass M, The Relation Between W

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Modified 4 Year Ago
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147 views
4 Years Ago

The Work Done On A Particle Of Mass By A Force K[x/x^2 + Y^2 I + Y/(x^+y^2) 3/2 J ] K Bring A Contract Of Appropriate Dimensions When The Particle Is Taken From The Point (a,b) To The Point (0,a)

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4 Years Ago

A Block Of Mass 2 Kg Is Free To Move Along The X-axis. It Is At Rest And From T = 0 Onwards It Is Subjected To A Time-dependent Force F(t) In The X Direction. The Force F(t) Varies With T As Shown In

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4 Years Ago

When A Rubber Band Is Stretched By A Distance X, It Exerts A Restoring Force Of Magnitude F = Ax + Bx^2, Where A And B Are Constants. The Work Done In Stretching The Unstretched Rubber Band By L Is

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Modified 4 Year Ago
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4 Years Ago

A Piece Of Wire Is Bent In The Shape Of A Parabola Y = Kx^2 (y-axis Vertical) With A Bead Of Mass M On It. The Bead Can Slide On The Wire Without Friction. It Stays At The Lowest Point Of The Parabola

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Modified 4 Year Ago
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4 Years Ago

A Ball Is Dropped From Height 20 M. If Coefficient Of Restitution Is 0.9 What Will Be The Height Attained After First Bounce?

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4 Years Ago

For Inelastic Collision Between Two Spherical Rigid Bodies

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5 Years Ago

A Particle Moves From A Point

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Modified 5 Year Ago
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5 Years Ago

A 50kg Man With 20kg Load On His Head Climbs Up 20 Steps Of 0.25m Height Each

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99 of 46300 Questions

Recent Questions

If The Kinetic Energy Of A Body Is Increased Two Times, Its Momentum Will

Two Balls Of Masses 2 G And 6 G Are Moving With Kinetic Energy In The Ratio Of 3 : 1. What Is The Ratio Of Their Linear Momenta?

A Body Of Mass 5 Kg Is Thrown Vertically Up With A Kinetic Energy Of 490 J. The Height At Which The Kinetic Energy Of The Body Becomes Half Of The Original Value Is

Two Bodies Of Masses M1 And M2 Are Acted Upon By Constant Force F For A Time T. They Start From Rest And Acquire Kinetic Energies E1 And E2, Respectively. Then, E1/E2 Is

Potential Energy Of A Particle Is To Î± Coordinate By Equation X^2 - 2x Will Be Equilibrium At

A Particle Of Mass 4m Which Is At Rest Explodes Into Three Fragments. Two Of The Fragments Each Of Mass M Are Found To Move With A Speed V Each Mutually Perpendicular Directions. The Total Energy Rele

The Magnitude Of Momentum Of Particle Is Increased By 100%. The Increase In Its Kinetic Energy Is

A Particle Which Is Constrained To Move Along The X-axis, Is Subjected To A Force In The Same Direction Which Varies With The Distance X Of The Particle From The Origin Is F (x) = - Kx + Ax^3 . Here K

A Spring Of Force Constant 800 Nm^-1 Has An Extension Of 5cm. The Work Done In Extending It From 5 Cm To 15 Cm Is

A Bullet Of Mass 10 G Is Fired Horizontally With A Velocity 1000 Ms^-1 From A Rifle Situated At A Height 50 M Above The Ground. If The Bullet Reaches The Ground With A Velocity 500 Ms^-1, The Work Don

If W1, W2, And W3 Represent The Work Done In Moving A Particle From A To B Along Three Different Different Paths 1,2 And 3 Respectively (as Show )in The Gravitational Field Of A Point Mass M, Find The

An Ideal Spring With Spring-constant K Is Hung From The Ceiling And A Block Of Mass M Is Attached To Its Lower End. The Mass Is Released With The Spring Initially Unstretched. Then The Maximum

A Particle Of Mass 100 G Is Thrown Vertically Upwards With A Speed Of 5 Ms^-1. The Work Done By The Force Of Gravity During The Time, The Particle Goes Up Is

A Mass Of M Kg Is Suspended By A Weightless String. The Horizontal Force That Is Required To Displace It Until The String Makes An Angle Of 45Â° With The Initial Vertical Direction Is

A Body Moves A Distance Of 10 M Along A Straight Line Under A Action Of 5 N Force. If Work Done Is 25 J, Then Angle Between The Force And Direction Of Motion Of The Body Will Be

When A Spring Is Stretched By A Distance X It Experts A Force Given By F (- 5x - 16x^3) N The Work Done When The Spring Stretched From 0.1 M To Done When The Spring Is Stretched From

4 M^3 Of Water Is To Be Pumped To A Height Of 20 M And Forced Into A Reservoir At A Pressure Of 2 X 10^5 Nm^-2. The Work Done By The Motor Is (given, External Pressure =10^5 Nm^-2)

A Tennis Ball Is Dropped On A Horizontal Smooth Surface. It Bounces Back To Its Original Position After Hitting The Surface. The Force On The Ball During The Collision Is Proportional To The Length Of

A Tennis Ball Is Dropped On A Horizontal Smooth Surface. It Bounces Back To Its Original Position After Hitting The Surface. The Force On The Ball During The Collision Is Proportional To The Length Of

The Work Done By A Force Acting On A Body Is As Shown In The Graph. The Total Work Done In Covering An Initial Distance Of 20 M Is

A Spring Of Force-constant K Is Cut Into Two Pieces Such That One Piece Is Double The Length Of The Other. Then The Long Piece Will Have A Force-constant Of

If W1, W2 And W3 Are The Work Done In Moving A Particle From A And B Along Three Different Paths 1, 2 And 3 Respectively (as Shown) In The Gravitational Field Of A Point Mass M, The Relation Between W

The Work Done On A Particle Of Mass By A Force K[x/x^2 + Y^2 I + Y/(x^+y^2) 3/2 J ] K Bring A Contract Of Appropriate Dimensions When The Particle Is Taken From The Point (a,b) To The Point (0,a)

A Block Of Mass 2 Kg Is Free To Move Along The X-axis. It Is At Rest And From T = 0 Onwards It Is Subjected To A Time-dependent Force F(t) In The X Direction. The Force F(t) Varies With T As Shown In

When A Rubber Band Is Stretched By A Distance X, It Exerts A Restoring Force Of Magnitude F = Ax + Bx^2, Where A And B Are Constants. The Work Done In Stretching The Unstretched Rubber Band By L Is

A Piece Of Wire Is Bent In The Shape Of A Parabola Y = Kx^2 (y-axis Vertical) With A Bead Of Mass M On It. The Bead Can Slide On The Wire Without Friction. It Stays At The Lowest Point Of The Parabola

A Ball Is Dropped From Height 20 M. If Coefficient Of Restitution Is 0.9 What Will Be The Height Attained After First Bounce?

For Inelastic Collision Between Two Spherical Rigid Bodies

A Particle Moves From A Point

A 50kg Man With 20kg Load On His Head Climbs Up 20 Steps Of 0.25m Height Each

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