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AD Is An Altitude Of An Equilateral Triangle ABC. On AD As Base Another Equilateral
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Two Isosceles Triangles Have Equal Vertical Angles And Their Areas
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If The Areas Of Two Similar Triangles Are 81 Cm Square And 49 Cm Square Respectively
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In The Given Figure, DE || BC, DE = 4 Cm, BC = 8 Cm
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In The Given Figure, S And T Are Points On The Sides PQ And PR Respectively Of Triangle PQR, Such That PT = 2
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Triangle ABC And Triangle DEF Are Similar And AB = 1/3 DE, Then Find
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Prove That The Line Segment Joining The Mid-points Of The Sides Of A Triangle From Four
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In The Given Figure, L || M And Line Segments AB, CD And EF
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In The Given Figure, AB || PQ || CD, AB = X Units
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In The Given Figure, If AB || DC And AC, PQ Intersect
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In The Adjoining Figure, ABC Is A Triangle Right Angled At B And BD
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In The Given Figure, If Angle BAC = 90 Degree And AD
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P And Q Are The Points On Sides AB And AC, Respectively
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