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Two Springs Have Spring Constants KA And KB And KA > KB . The Work Required To Stretch Them By Same Extension Will Be

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A Mass M Is Suspended From A Light Spring. An Additional Mass M Added Displaces The Spring Further By A Distance X. Now The Combined Mass Will Oscillate On The Spring With Period

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A Mass M Attached To A Spring Oscillates Every 2 Sec. If The Mass Is Increased By 2 Kg, Then Time-period Increases By 1 Sec. The Initial Mass Is

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A Mass M Is Suspended By Means Of Two Coiled Spring Which Have The Same Length In Unstretched Condition As In Figure. Their Force Constant Are K1 And K2 Respectively. When Set Into Vertical Vibratio

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When A Mass M Is Attached To A Spring, It Normally Extends By 0.2 M. The Mass M Is Given A Slight Additional Extension And Released, Then Its Time Period Will Be

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The Frequency Of Oscillation Of The Springs Shown In The Figure Will Be

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A Mass M Is Suspended By Two Springs Of Force Constants K1 And K2 Respectively As Shown In The Diagram. The Total Elongation (stretch) Of The Two Springs Is

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The Force Constants Of Two Springs Are K_1 And K_2 . Both Are Stretched Till Their Elastic Energies Are Equal. If The Stretching Forces Are F_1 And F_2 , Then

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A Body Of Mass 0.01 Kg Executes Simple Harmonic Motion (S.H.M.) About X = 0 Under The Influence Of A Force Shown Below : The Period Of The S.H.M. Is

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A Mass M Is Suspended Separately By Two Different Springs Of Spring Constant K1 And K2 Gives The Time-period T_1 And T_2 Respectively. If Same Mass M Is Connected By Both Springs As Shown In Figure

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One-fourth Length Of A Spring Of Force Constant K Is Cut Away. The Force Constant Of The Remaining Spring Will Be

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Two Springs Of Force Constants K And 2K Are Connected To A Mass As Shown Below. The Frequency Of Oscillation Of The Mass Is

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A Mass M Is Suspended From A Spring Of Negligible Mass. The Spring Is Pulled A Little And Then Released So That The Mass Executes S.H.M. Of Time Period T. If The Mass Is Increased By M, The Time Perio

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A Particle At The End Of A Spring Executes Simple Harmonic Motion With A Period T1, While The Corresponding Period For Another Spring Is T2. If The Period Of Oscillation With The Two Springs In Series

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A Spring Has Length L And Spring Constant K. If Spring Is Divided In Two Equal Parts Then Spring Constant Is

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A Sphere Of Radius R Is Kept On A Concave Mirror Of Radius Of Curvature R. The Arrangement Is Kept On A Horizontal Table (the Surface Of Concave Mirror Is Frictionless And Sliding Not Rolling). If The

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Infinite Springs With Force Constants K, 2k, 4k And 8kâ€¦. Respectively Are Connected In Series. The Effective Force Constant Of The Spring Will Be

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Two Springs Are Connected To A Block Of Mass M Placed On A Frictionless Surface As Shown Below. If Both The Springs Have A Spring Constant K, The Frequency Of Oscillation Of The Block Is

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A Simple Pendulum Is Suspended From The Roof Of A Train. The Train Is Moving With Acceleration 49\,cm/ Sec ^2 . By What Angle To The Vertical, Its String Will Be Inclined

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A Simple Pendulum Consisting Of A Ball Of Mass M Is Tied To A Spring Of Length L Is Made To Swing On A Circular Arc Of Angle Q In A Vertical Plane. At The End Of This Arc, Another Ball Of Mass M Is Pl

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If The Length Of Secondâ€™s Pendulum Is Decreased By 2%, How Many Seconds It Will Lose Per Day

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If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

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If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

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The Period Of Oscillation Of A Simple Pendulum Of Length L Suspended From The Roof Of A Vehicle Which Moves Without Friction Down An Inclined Plane Of Inclination A, Is Given By

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The Period Of Oscillation Of A Simple Pendulum Of Constant Length At Earth Surface Is T. Its Period Inside A Mine Is

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A Hollow Sphere Is Filled With Water Through A Small Hole In It. It Is Then Hung By A Long Thread And Made To Oscillate. As The Water Slowly Flows Out Of The Hole At The Bottom, The Period Of Oscillat

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In Case Of A Simple Pendulum, Time Period Versus Length Is Depicted By

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A Simple Pendulum Of Length L Has A Brass Bob Attached At Its Lower End. Its Period Is T. If A Steel Bob Of Same Size, Having Density X Times That Of Brass, Replaces The Brass Bob And Its Length Is Ch

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A Chimpanzee Swinging On A Swing In A Sitting Position, Stands Up Suddenly, The Time Period Will

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Two Simple Pendulum Of Length 5 M And 20 M Respectively Are Given Small Linear Displacement In One Direction At The Same Time. They Will Again Be In The Phase When The Pendulum Of Shorter Length Has C

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Two Springs Have Spring Constants KA And KB And KA > KB . The Work Required To Stretch Them By Same Extension Will Be

A Mass M Is Suspended From A Light Spring. An Additional Mass M Added Displaces The Spring Further By A Distance X. Now The Combined Mass Will Oscillate On The Spring With Period

A Mass M Attached To A Spring Oscillates Every 2 Sec. If The Mass Is Increased By 2 Kg, Then Time-period Increases By 1 Sec. The Initial Mass Is

A Mass M Is Suspended By Means Of Two Coiled Spring Which Have The Same Length In Unstretched Condition As In Figure. Their Force Constant Are K1 And K2 Respectively. When Set Into Vertical Vibratio

When A Mass M Is Attached To A Spring, It Normally Extends By 0.2 M. The Mass M Is Given A Slight Additional Extension And Released, Then Its Time Period Will Be

The Frequency Of Oscillation Of The Springs Shown In The Figure Will Be

A Mass M Is Suspended By Two Springs Of Force Constants K1 And K2 Respectively As Shown In The Diagram. The Total Elongation (stretch) Of The Two Springs Is

The Force Constants Of Two Springs Are K_1 And K_2 . Both Are Stretched Till Their Elastic Energies Are Equal. If The Stretching Forces Are F_1 And F_2 , Then

A Body Of Mass 0.01 Kg Executes Simple Harmonic Motion (S.H.M.) About X = 0 Under The Influence Of A Force Shown Below : The Period Of The S.H.M. Is

A Mass M Is Suspended Separately By Two Different Springs Of Spring Constant K1 And K2 Gives The Time-period T_1 And T_2 Respectively. If Same Mass M Is Connected By Both Springs As Shown In Figure

One-fourth Length Of A Spring Of Force Constant K Is Cut Away. The Force Constant Of The Remaining Spring Will Be

Two Springs Of Force Constants K And 2K Are Connected To A Mass As Shown Below. The Frequency Of Oscillation Of The Mass Is

A Mass M Is Suspended From A Spring Of Negligible Mass. The Spring Is Pulled A Little And Then Released So That The Mass Executes S.H.M. Of Time Period T. If The Mass Is Increased By M, The Time Perio

A Particle At The End Of A Spring Executes Simple Harmonic Motion With A Period T1, While The Corresponding Period For Another Spring Is T2. If The Period Of Oscillation With The Two Springs In Series

A Spring Has Length L And Spring Constant K. If Spring Is Divided In Two Equal Parts Then Spring Constant Is

A Sphere Of Radius R Is Kept On A Concave Mirror Of Radius Of Curvature R. The Arrangement Is Kept On A Horizontal Table (the Surface Of Concave Mirror Is Frictionless And Sliding Not Rolling). If The

Infinite Springs With Force Constants K, 2k, 4k And 8kâ€¦. Respectively Are Connected In Series. The Effective Force Constant Of The Spring Will Be

Two Springs Are Connected To A Block Of Mass M Placed On A Frictionless Surface As Shown Below. If Both The Springs Have A Spring Constant K, The Frequency Of Oscillation Of The Block Is

A Simple Pendulum Is Suspended From The Roof Of A Train. The Train Is Moving With Acceleration 49\,cm/ Sec ^2 . By What Angle To The Vertical, Its String Will Be Inclined

A Simple Pendulum Consisting Of A Ball Of Mass M Is Tied To A Spring Of Length L Is Made To Swing On A Circular Arc Of Angle Q In A Vertical Plane. At The End Of This Arc, Another Ball Of Mass M Is Pl

If The Length Of Secondâ€™s Pendulum Is Decreased By 2%, How Many Seconds It Will Lose Per Day

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

The Period Of Oscillation Of A Simple Pendulum Of Length L Suspended From The Roof Of A Vehicle Which Moves Without Friction Down An Inclined Plane Of Inclination A, Is Given By

The Period Of Oscillation Of A Simple Pendulum Of Constant Length At Earth Surface Is T. Its Period Inside A Mine Is

A Hollow Sphere Is Filled With Water Through A Small Hole In It. It Is Then Hung By A Long Thread And Made To Oscillate. As The Water Slowly Flows Out Of The Hole At The Bottom, The Period Of Oscillat

In Case Of A Simple Pendulum, Time Period Versus Length Is Depicted By

A Simple Pendulum Of Length L Has A Brass Bob Attached At Its Lower End. Its Period Is T. If A Steel Bob Of Same Size, Having Density X Times That Of Brass, Replaces The Brass Bob And Its Length Is Ch

A Chimpanzee Swinging On A Swing In A Sitting Position, Stands Up Suddenly, The Time Period Will

Two Simple Pendulum Of Length 5 M And 20 M Respectively Are Given Small Linear Displacement In One Direction At The Same Time. They Will Again Be In The Phase When The Pendulum Of Shorter Length Has C

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