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The Circular Motion Of A Particle With Constant Speed Is
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The Displacement Of A Particle In SHM Various According To The Relation X = 4 (cosπt + Sin Pie T). The Amplitude Of The Particle Is
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In Arrangement Given In Figure, If The Block Of Mass M Is Displaced, The Frequency Is Given By
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Two Springs Have Spring Constants KA And KB And KA > KB . The Work Required To Stretch Them By Same Extension Will Be
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One-fourth Length Of A Spring Of Force Constant K Is Cut Away. The Force Constant Of The Remaining Spring Will Be
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Two Springs Of Force Constants K And 2K Are Connected To A Mass As Shown Below. The Frequency Of Oscillation Of The Mass Is
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A Spring Has Length L And Spring Constant K. If Spring Is Divided In Two Equal Parts Then Spring Constant Is
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If The Length Of Second’s Pendulum Is Decreased By 2%, How Many Seconds It Will Lose Per Day
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