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Speed Of Two Identical Cars Are U And 4u At A Specific Instant. The Ratio Of The Respective Distances In Which The Two Cars Are Stopped From That Isntant Is

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An Elevator Car, Whose Floor To Ceiling Distance Is Equal To 2.7 M, Starts Ascending With Constant Acceleration Of 1.2 Ms^-2, Sec After The Start

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The Velocity Of A Particle Is V=v0 + Gt + Ft^2. If Its Position Is X=0 At T=0, Then Its Displacement After Unit Time (t=1) Is

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A Body Of Mass 10 Kg Is Moving With A Constant Velocity Of 10 M/s. When A Constant Force Acts For 4 Sec On It, Ot Moves With A Velocity 2 M/sec In The Opposite Direction.

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Two Cars A And B Are Travelling In The Same Direction With Velocities V1 And V2(v1>v2). When The Car A Is At A Distance D Ahead Of The Car B, The Driver Of The Car.

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A Particle Moving With A Uniform Acceleration Travels 24 M And 64 M In The First Two Consecutive Intervals Of 4 Sec Each. Its Initial Velocity

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Which Of The Following Four Statements Is False?

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The Velocity Of A Body Depends On Time According To The Equation V=20 + 0.1 T^2. The Body Is Undergoing

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A Man Is 45 M Behind The Bus When The Bus Start Accelerating From Rest With Acceleration 2.5 M/s^2. With What Minimum Velocity Should The Man Start Running To Catch The Bus?

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A Particle Moves Along X-axis Is X=4(t-2) + A(t-2)^2. Which Of The Following Is True?

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A Body Starting From Rest Moves With Constant Acceleration. The Ratio Of Distance Covered By The Body During The 5th Sec To That Covered In 5 Sec Is

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The Relation Between Time And Distance Is T=alpha (x)^2 + Beta X, Where Alpha And Beta Are Constants. The Retardation Is

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The Relation Between Time And Distance Is T=alpha (x)^2 + Beta X, Where Alpha And Beta Are Constants. The Retardation Is

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The Acceleration A Of A Particle Starting From Rest Varies With Time According To Relation A=alpha T+beta. The Velocity Of The Particle After A Time T Will Be

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A Particle Starts From Rest T T=0 And Moves In A Straight Line With An Acceleration As Shown Below. The Velocity Of The Particle At T=3 S Is

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A Bus Begins To Move With An Acceleration Of 1 Ms^-2. A Man Who Is 48 M Behind The Bus Starts Running At 10 Ms^-1 To Catch The Bus. The Man Will Be Able To Catch The Bus After

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A Car Moves A Distance Of 200 M. It Covers First Half Of The Distance At Speed 60 Kmh^-1 And The Second Half At Speed V. The Average Speed Is 40 Kmh^-1, The Value Of V Is

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A Bullet Fired Into A Fixed Target Loses Half Of Its Velocity After Penetrating 3 Cm. How Much Further It Will Penetrate Before Coming To Rest Assuming That It Faces Constant Resistance To Motion?

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The Correct Statement From The Following Is

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A Particle Moves For 20 Sec With Velocity 3 M/s And Then Velocity 4 M/s For Another 20 Sec And Finally Moves With Velocity 5 M/s For Next 20 Sec.

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The Numerical Ratio Of Displacement To The Distance Covered Is Always

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Which Of The Following Options Is Correct For The Object Having A Straight Line Motion Represented By The Following Graph?

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A Person Travels Along A Straight Road For The First Half Time With A Velocity V1 And The Next Time With A Velocity V2. The Mean Velocity V Of The Man Is

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The Ratio Of The Numerical Values Of The Average Velocity And Average Speed Of A Body Is Always

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A Particle Moves Along A Semicircle Of Radius 10 M In 5 Sec. The Velocity Of The Particle Is

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A Boy Walks To His School At A Distance Of 6 Km With Constant Speed Of 2.5 Km/hr And Walks Back With A Constant Speed Of 4 Km/hr.

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A Bullet Emerges From A Barrel Of Length 1.2 M With A Speed Of 640 Ms^-1. Assuming Constant Acceleration, The Approximate Time That It Spends In The Barrel After The Gun Is Fired Is

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The Displacement-time Graph For Two Particles. A And B Are Straight Llines Inclined At Angles Of 30 Degree And 60 Degree With The Time Axis. The Ratio Of Velocities Of Va:Vb Is

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A Body Is Moving Along A Straight Line Path With Constant Velocity. At An Instant Of Time The Distance Travelled By It Is S And Its Displacement Is D, Then

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The Displacement Of A Body Along X-axis Depends On Time As âˆšx=1+1. Then, The Velocity Of Body

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586 of 46300 Questions

Recent Questions

Speed Of Two Identical Cars Are U And 4u At A Specific Instant. The Ratio Of The Respective Distances In Which The Two Cars Are Stopped From That Isntant Is

An Elevator Car, Whose Floor To Ceiling Distance Is Equal To 2.7 M, Starts Ascending With Constant Acceleration Of 1.2 Ms^-2, Sec After The Start

The Velocity Of A Particle Is V=v0 + Gt + Ft^2. If Its Position Is X=0 At T=0, Then Its Displacement After Unit Time (t=1) Is

A Body Of Mass 10 Kg Is Moving With A Constant Velocity Of 10 M/s. When A Constant Force Acts For 4 Sec On It, Ot Moves With A Velocity 2 M/sec In The Opposite Direction.

Two Cars A And B Are Travelling In The Same Direction With Velocities V1 And V2(v1>v2). When The Car A Is At A Distance D Ahead Of The Car B, The Driver Of The Car.

A Particle Moving With A Uniform Acceleration Travels 24 M And 64 M In The First Two Consecutive Intervals Of 4 Sec Each. Its Initial Velocity

Which Of The Following Four Statements Is False?

The Velocity Of A Body Depends On Time According To The Equation V=20 + 0.1 T^2. The Body Is Undergoing

A Man Is 45 M Behind The Bus When The Bus Start Accelerating From Rest With Acceleration 2.5 M/s^2. With What Minimum Velocity Should The Man Start Running To Catch The Bus?

A Particle Moves Along X-axis Is X=4(t-2) + A(t-2)^2. Which Of The Following Is True?

A Body Starting From Rest Moves With Constant Acceleration. The Ratio Of Distance Covered By The Body During The 5th Sec To That Covered In 5 Sec Is

The Relation Between Time And Distance Is T=alpha (x)^2 + Beta X, Where Alpha And Beta Are Constants. The Retardation Is

The Relation Between Time And Distance Is T=alpha (x)^2 + Beta X, Where Alpha And Beta Are Constants. The Retardation Is

The Acceleration A Of A Particle Starting From Rest Varies With Time According To Relation A=alpha T+beta. The Velocity Of The Particle After A Time T Will Be

A Particle Starts From Rest T T=0 And Moves In A Straight Line With An Acceleration As Shown Below. The Velocity Of The Particle At T=3 S Is

A Bus Begins To Move With An Acceleration Of 1 Ms^-2. A Man Who Is 48 M Behind The Bus Starts Running At 10 Ms^-1 To Catch The Bus. The Man Will Be Able To Catch The Bus After

A Car Moves A Distance Of 200 M. It Covers First Half Of The Distance At Speed 60 Kmh^-1 And The Second Half At Speed V. The Average Speed Is 40 Kmh^-1, The Value Of V Is

A Bullet Fired Into A Fixed Target Loses Half Of Its Velocity After Penetrating 3 Cm. How Much Further It Will Penetrate Before Coming To Rest Assuming That It Faces Constant Resistance To Motion?

The Correct Statement From The Following Is

A Particle Moves For 20 Sec With Velocity 3 M/s And Then Velocity 4 M/s For Another 20 Sec And Finally Moves With Velocity 5 M/s For Next 20 Sec.

The Numerical Ratio Of Displacement To The Distance Covered Is Always

Which Of The Following Options Is Correct For The Object Having A Straight Line Motion Represented By The Following Graph?

A Person Travels Along A Straight Road For The First Half Time With A Velocity V1 And The Next Time With A Velocity V2. The Mean Velocity V Of The Man Is

The Ratio Of The Numerical Values Of The Average Velocity And Average Speed Of A Body Is Always

A Particle Moves Along A Semicircle Of Radius 10 M In 5 Sec. The Velocity Of The Particle Is

A Boy Walks To His School At A Distance Of 6 Km With Constant Speed Of 2.5 Km/hr And Walks Back With A Constant Speed Of 4 Km/hr.

A Bullet Emerges From A Barrel Of Length 1.2 M With A Speed Of 640 Ms^-1. Assuming Constant Acceleration, The Approximate Time That It Spends In The Barrel After The Gun Is Fired Is

The Displacement-time Graph For Two Particles. A And B Are Straight Llines Inclined At Angles Of 30 Degree And 60 Degree With The Time Axis. The Ratio Of Velocities Of Va:Vb Is

A Body Is Moving Along A Straight Line Path With Constant Velocity. At An Instant Of Time The Distance Travelled By It Is S And Its Displacement Is D, Then

The Displacement Of A Body Along X-axis Depends On Time As âˆšx=1+1. Then, The Velocity Of Body

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