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Consider A Rubber Ball Freely Falling From A Height H=4.9 M Onto A Horizontal Elastic Plate.
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The Displacement-time Graphs Of Two Moving Particles Make Angles Of 30 Degree And 45 Degree With The X-axis. The Ratio Of Their Velocities Is
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Given Below Are Four Curves Describing Variation Of Velocity With Time Of A Particle.
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Two Cars A And B Are Traveling In The Same Direction With Velocities V1 And V2 (v1>v2). When The Car A Is At A Distance D Behind The Car B
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The Acceleration Experienced By A Moving Boat After Its Engine Is Cut Off, Is Given By A=-kv^3, Where K Is A Constant.
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A Boat Travels 50 Km Due East, Then 120 Km Due North And Finally It Comes Back To The Starting Point Through The Shortest Distance.
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The Coordinates Of A Moving Particle At Any Time T Are Given By X=alpha (t)^3 And Y=beta (t)^3. The Speed Of The Particle At Time T Is Given By
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The Velocity Of Particle Is V=v0+gt+ft^2. If Its Position Is X=0 At T=0, Then Its Displacement After Unit Time (t=1) Is
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A Body Is Projected Vertically Upwards. The Times Corresponding To Height H While Ascending And While Descending Are T1 And T2, Respectively.
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A Body Of Mass M Is Thrown Upwards At An Angle 0 With The Horizontal With Velocity V.
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A Body Of Mass M Moving Along A Straight Line Covers Half The Distance With A Speed Of 2 Ms^-1.
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The Area Under Acceleration-time Graph Gives
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A Car Is Travelling At 72 Kmh^-1 And Is 20 M From A Barrier When The Driver Puts On The Brakes. The Car Hits The Barrier 2 S Later.
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The Relation Between Time T And Distance X Is T=a(x)^2 + Bx, Where, A And B Are Constants. The Acceleration Is
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A Body Dropped From The Top Of A Tower Fall Through 60 M During The Last 2 S Of Its Fall. The Height Of Tower Is
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