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The Value Of N For Which X^n+1+y^n+1 Divide By X^n+y^n Is The Geometric Mean Of X And Y Is
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Sum Of N Terms Of The Following Series 1^3+3^3+5^3+7^3+...is
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If A, B,c Are In G.P. Then Log A X, Log B X, Log C X In
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The Value Of F At X=0 So That The Function F(x)=2^x-2^-x, X Is Not Equal To 0, Is Continuous At X=0, Is
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If F(x) Is Equal To 2x+1/3x-2, Then (fof)(2) Is Equal To
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Lim X Tense To A^x-b^x/e^x-1=
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The Function F(x) =|x|+|x-1| Is
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F(x)={[x]+[-x],when X Is Not Equal To 2,{Delta , When X Is Equal To 0. If F(x) Is Continuous At X =2, The Value Of Delta Will Be
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If The Function F(x) Is Equal To {x^2-(A+2)x+A/x-2, For X Is Not Equal To 2, {2, For X=2 Is Continuous At X=2, Then
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The Value Of Lim X Tense To 1(x+x^2+.....x^n-n/x-1) Is
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The Value Of F(0) So That The Function F(x)=1-cos(1-cosx)/x^4 Is Continuous Everywhere Is
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Lim X Tense To 0 Sin|x|/x Is Equal To
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The Value Of Lim X Tense To 0 Sin^2x + Cosx-1/x^2 Is
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The Domain Of The Function F(x)=under Root Cos^-1(1-|x|/2) Is
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A={1,2,3,4},B={1,2,3,4,5,6} Are Two Sets And Function F:A Is Tense To B Is Defined By F(x)=x+2; Where Is X€A,then The Function Of F Is
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The Number Of Points At Which The Function F(x)=|x-0.5|+|x-1|+ Tan X Does Not Have A Derivative In The Interval
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Lim X Tense To Infinite Cos X =
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F(x)={6x^5,x<0,{2a+x, X>0 Is Continuous At X=0,then A=
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Lim X Tense To E (1n X)^ 1/1-1n X=
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Let F(x) =[x^3 -3][x]=G.I.F. Then The No. Of Points In The Interval (1,2) Where Function Is Discontinuous Is
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The Value Of Lim X Tense To π/2 (sin X)^ Tan X Is
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Lim X Tense To N(-1)^[x] Is Equal To
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Let F(x)={1 Where X<0 ,{1+sin X Where 0<=x<=Ï€/2,then What Is The Value Of F(x) At X=0
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The Value Of P For Which The Function F(x)={(4^x-1)^3}/sin X/p Log [1+x^2/3],x Is Not Equal To 0, May Be Continuous At X=0, 12(log4)^3,x=0 Is
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If F(x)={x^2 -3,2
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If F(x)=sin^2 X And The Composite Function G{f(x)}=|sin X|,then The Function G(x) Is Equal To
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