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The Solution Of The Equation Log7 Log5 (√x^2 +5 +x) = 0
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D^n/dx^n (log X)=
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First Term Of The 11th Group In The Following Groups (1), (2,3,4), (5,6,7,8,9),...........is
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If The Set Of Natural Numbers Is Partitioned Into Subsets S 1={1}, S 2={2,3}, S 3={4,5,6} And So On. Then The Sum Of The Terms In S 50 Is
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The Sum Of I-2-3i+4+....... Upto 100 Terms, Where I=root (-1) Is
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If A, B, C, D Are In H.P., Then Ab+bc+cd Is Equal To
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The Value Of A^(logb X), Where A = 0.2, B = Root 5, X = 1/4+1/8+1/16+........ To Infinity Is
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If The Product Of Three Consecutive Terms Of G.P. Is 216 And The Sum Of Product Of Pair-wise Is 156, Then The Numbers Will Be
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If The Sides Of A Right Angled Triangle Are In A.P., Then The Sides Are Proportional To
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If A Be An Arithmetic Mean Between Two Numbers And S Be The Sum Of N Arithmetic Means Between The Same Numbers, Then
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A Number Is The Reciprocal Of The Other. If The Arithmetic Mean Of The Two Numbers Be 13/12, Then The Numbers Are
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If The Sum Of The 10 Terms Of An A.P. Is 4 Times To The Sum Of Its 5 Terms, Then The Ratio Of First Term And Common Difference Is
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The First Term Of An A.P. Of Consecutive Integers Is (p^2)+1. The Sum Of (2p+1) Terms Of This Series Can Be Expressed As
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Modified 5 Year Ago
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The Geometric Mean Of 1, 2, 2^2,...., 2^n Is
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If (3+5+7+........ To N Terms)/(5+8+11+.......to 10 Terms) Is Equal To 7, Then The Value Of N Is
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If A And B Are Two Different Positive Real Numbers, Then Which Of The Following Relations Is True
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After Inserting N A.M.s Between 2 And 38, The Sum Of The Resulting Progression Is 200. The Value Of N Is
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The Harmonic Mean Of (a/1-ab) And (a/1+ab) Is
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If S Is The Sum Of An Infinite G.P., The First Term A Then The Common Ratio R Given By
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There Are 15 Terms In An Arithmetic Progression. Its First Term Is 5 And Their Sum Is 390. The Middle Term Is
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If X Is Added To Each Of Numbers 3, 9, 21 So That The Resulting Numbers May Be In G.P., Then The Value Of X Will Be
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The Sum Of 1+(2/5)+(3/5^2)+(4/5^3)+......... Upto N Terms Is
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Modified 5 Year Ago
