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If A Car Covers 2/5th Of The Total Distance With V1 Speed And 3/5th Distance With V2 Then Average Speed Is
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A Man Walks On A Straight Road From His Home To Market 2.5 Km Away With A Speed Of 5 Km/hr. Finding The Market Closed
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A 150 M Long Train Is Moving With A Uniform Velocity Of 45 Km/hr. The Time Taken By The Train To Cross A Bridge Of Length 850 M Is
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Which Of The Following Is A One Dimensional Motion
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A Train Has A Speed Of 60 Km/hr. For The First One Hour And 40 Km/hr. For The Next Half Hour. Its Average Speed In Km/hr Is
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One Car Moving On A Straight Road Covers One Third Of The Distance With 20 Km/hr And The Rest With 60 Km/hr. The Average Speed Is
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A Car Moves From X To Y With A Uniform Speed Vu And Returns To X With A Uniform Speed Vd. The Average Speed For This Round Trip Is
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A Graph Is Drawn Between Velocity And Time For The Motion Of A Particle. The Area Under The Curve Between The Time Intervals T1 And T2 Gives
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An Aeroplane Files 400 M North And 300 M South And Then Files 1200 M Upwards Then Net Displacement Is
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The V-t Graph For A Particle Is As Shown. The Distance Travelled In The First 4 S Is
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Look At The Graph (a) To (d) Carefully And Indicate Which Of These Possibly Represents One Dimensional Motion Of A Particle?
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If The Figure Below Represents A Parabola, Identify The Physical Quantities Representing Y And X For Constant Acceleration
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A Body Starts From Rest And Moves With Uniform Acceleration. Which Of The Following Graphs Represents Its Motion.
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An Object Dropped From Rest. Its Velocity-time Graph Is
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A Particle Starts From Rest At T=0 And Moves In A Straight Line With An Acceleration As Shown In Figure.
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A Body Is At X=0. At T=0, It Starts Moving In The Positive X-direction With A Constant Acceleration. At The Same Instant Another Body Passes
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A Particle Starts From Rest At T=0 And Undergoes An Acceleration A (in Ms^-1 With Time T In Second Which Is As Shown.
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