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The Maximum Possible Value Of X^2 + Y^2 - 4x-6y, Where X, Y € R, Subject To The Condition | X + Y | + | X - Y | = 4, Is
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If | X + 2 | + Y = 5 And X - | Y |=1 Then The Value Of X+y Is
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F(x) = √1/3-x-| X -3| Is Defined For
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The Solution Set Of Inequality 1/2^x -1>1/1-2^x-1 Is
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The Complete Set Of Values Of X For Which
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Number Of Integers Satisfying X+√3-x ≥ √3-x +3 Is
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Log7log7√7(√7√7) =
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The Value Of √(log^2↓0.5^4) Is
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The Value Of (0.05)^log√20^(0.1+0.01+0.001+.....)
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€^_n=1/log2n(a) =
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If A^2 +4b^2 = 12ab, Then Log(a + 2b) Is
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If Logk X.log5 K = Logx 5,k ≠1, K>0, Then X Is Equal To
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If 2^x.3^x+4 = 7^x, Then X =
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The Value Of 7 Log2 16/15+log2 25/24+3log2 81/80 Is
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The Value Of Log2. Log3....log100 100^99^98^..2^1 Is
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If Log√3 5 = A And Log√3 2 = B, Then Log √3 300 =
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If Loge (x^2 - 16)≤ Loge (4x - 11), Then
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If X = Logq(bc), Y = Logb(ca), Z = Logc(ab), Then Which Of The Following Is Equal To 1
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If Log0.04(x-1)>_ Log 0.2(x-1), Then X Belong To The Interval
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The Solution Of The Equation Log7 Log5 (√x^2 +5 +x) = 0
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The Value Of
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The Real Values Of X And Y For Which The Equation
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20 votes1 answer178 views
If A2 + B2 = 1, Then
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If Z And Z` Are Complex Numbers Such That
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Equation Is Given Below
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