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A Ball Is Projected Upwards From A Height H Above The Surface Of The Earth With Velocity V. The Time At Which The Ball Strikes The Ground Is
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A Stone Falls Freely From Rest From A Height H And It Travels A Distance 9h/25 In The Last Second. The Value Of H Is 25
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A Boy Standing At The Top Of A Tower Of 20 M Height Drops A Stone. Assuming G=10 M/s^-2, The Velocity With Which It Hits The Ground Is
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The Ratio Of The Distance Traversed, In Successive Intervals Of Time By A Body, Falling From Rest, Are
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Two Stones Of Equal Masses Are Dropped From A Rooftop Of Height H One After Another. Their Separation Distance Against Time Will
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A Ball Is Thrown Up Under Gravity (g=10 M/sec^2). Find Its Velocity After 1.0 Sec At Height Of 10 M.
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The Effective Acceleration Of A Body, When Thrown Upwards With Acceleration A Will Be
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A Packet Is Dropped From A Balloon Which Is Going Upwards With The Velocity 12 M/s, The Velocity Of The Packet After 2 Seconds Will Be
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If A Body Is Thrown Up With The Velocity Of 15 M/s Then Maximum Height Attained By The Body Is (g=10m/s^2)
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Two Balls Are Dropped From Heights H And 2h Respectively From The Earth Surface. The Ratio Of These Balls To Reach The Earth Is
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A Body Falls From A Height H=200 M (at New Delhi). The Ratio Of Distance Travelled In Each 2 Sec During T=0 To T=6 Second Of The Journey Is
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A Body Falling From A High Minaret Travels 40 M In The Last 2 Seconds Of Its Fall To Ground. Height Of Minaret In Meters Is (take G=10 M/s^2)
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A Cricket Ball Is Thrown Up With A Speed Of 19.6 M/s^-1. The Maximum Height It Can Reach Is
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0 votes0 answer77 views
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Time Taken By An Object Falling From Rest To Cover The Height Of H1 And H2 Is Respectively T1 And T2 Then The Ratio Of T1 To T2 Is
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A Body Projected Vertically Upwards With A Velocity U Returns To The Starting Point In 4 Seconds. If G=10 M/sec^2, The Value Of U Is
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Modified 5 Year Ago
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The Time Taken By A Block Of Wood (initially At Rest) To Side Down A Smooth Inclined Plane 9.8 M Long (angle Of Inclination Is 30 Degree) Is
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