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For Every Natural Number N, (n+1) Is Always
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For Natural Number N, (n!)^2 > N^n , If
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If N Is A Natural Number Then (n+1/2)^n ≥ N ! Is True When
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For Any Natural Number N, 2^n (n-1)!< N^n, If
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For Each N Epsilon N , The Correct Statement Is
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The Statement P(n)
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For A Natural Number N, Which One Is The Correct Statement
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10^n + 3(4^n+2) + 5 Is Divisible By (n Epsilon N)
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(2^3n - 1) Will Be Divisible By
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When 2^301 Is Divided By 5, The Least Positive Reminder Is
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7^9 + 9^7 Is Divisible By
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If N Is Positive Integer And Three Consecutive Coefficients In The Expansion Of (1+x)^n Are In The Ratio 6 : 33 : 110, Then N =
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The Coefficient Of Two Consecutive Terms In The Expansion Of (1+x)^n Will Be Equal, If
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Cube Root Of 217 Is
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If Ar Is The Coefficient Of X^r, In The Expansion Of
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The First Four Terms In The Expansion Of (1-x)^3/2 Will Be When
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The Coefficient Of X^r In The Expansion Of (1-x)^-2 Is
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If |x|< 1 Then The Coefficient Of X^n In The Expansion Of
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The Expression (2 + Under Root 2)^4 Has Value, Lying Between
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The Digit In The Unit Place Of The Number (183!) +3^183 Is
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The Number Of Integral Terms In The Expansion Of (under Root 3 + 8 Under Root 5)^256
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1+1/3x + 1.4/3.6x^2 + 1.4.7/3.6.9x^3 +..... Is Equal To
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The Sum Of 1 + N(1-1/x) + N(n+1)/2! (1-1/x)^2 +.....
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If |x|< 1, Then The Value Of
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If |x|> 1, Then (1+x)-2 =
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The Coefficient Of X^3 In The Expansion Of (1+3x)^2/1-2x Will Be
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1/(x^2 + 1/x)^4/3 Can Be Expanded By Binomial Theorem, If
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In The Expansion Of (1+x/1-x)^2, The Coefficient Of X^n Will Be
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1/3 Under Root 6-3x =
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