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Lim Theta-->0 5theta Cos Theta-2sin Theta/3theta+tan Theta =
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The Value Of LimX-->0 E^x+log(1+x)-(1-x)^-2/x^2 Is Equal To
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If A,b,c,d Are Positive, Then LimX-->infinity (1+1/a+bx)^c+dx =
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The Value Of LimX-->0 27^x-9^x-3^x+1/root 5-root 4+cosX Is
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The Value Of LimX-->infinity X^n/x^n+1 Where X<-1 Is
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The Value Of LimX-->infinity (x+1)(3x+4)/x^2(x-8) Is Equal To
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