363 of 46300 Questions
View AllRecent Questions
-
0 votes0 answer107 views
-
0 votes0 answer117 views
-
0 votes0 answer136 views4 Years Ago
If ( 1 + I Root( 3) ) Pw9 = A + Ib Then B Is Equal To
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer577 views
-
0 votes0 answer200 views
-
0 votes0 answer223 views
-
0 votes0 answer131 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer411 views
-
0 votes0 answer118 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer147 views
-
0 votes0 answer125 views
-
0 votes0 answer242 views4 Years Ago
If 0 Greater Amp ( Z ) Greater Pie, Then Amp( Z) -amp ( -z)
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer122 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer131 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer397 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer318 views4 Years Ago
Let Z Be A Purely Imaginary Number Such That Im(z)smaller 0. Then Arg (z) Is Equal To
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer138 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer116 views
-
0 votes0 answer124 views4 Years Ago
If Z1,z2 Are Two Complex Numbers Then | Z1 + Root( Z1(sq) - Z2(sq) ) | + |z1 - Root(z1(sq) - Z2(sq)| Is Equal To
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer130 views4 Years Ago
Let Z Be A Complex Number ( Not Lying On X-axis ) Of Maximum Modules Such That |z +1/z | = 1 Then
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer113 views4 Years Ago
If Z - I / Z + I (z =not Equal - I) Is A Purely Imaginary Number , The Z.z- Equal To
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer126 views
-
0 votes0 answer119 views4 Years Ago
The Value Of X And Y For Which The Number 3 + Ix(sq)y And X(sq) + Y + 4i Are Conjugate Complex Numbers Can Be
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer112 views
-
0 votes0 answer124 views4 Years Ago
If Z Is A Complex Number Such That Z(sq) =( Z-)(sq) Then
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer120 views
-
0 votes0 answer154 views
-
0 votes0 answer112 views4 Years Ago
For Any Two Complex Numbers Z1,z2 We Have | Z1 +z2 |(sq) =| Z1 |(sq) + |z2|(sq),then
JEE DiscussionsModified 4 Year Ago
-
0 votes0 answer119 views4 Years Ago
Modified 4 Year Ago
-
0 votes0 answer131 views