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0 votes0 answer129 views5 Years Ago
If Z1,z2 And Z3, Z4 Are Tow Pairs Of Cungugate Complex Number , Then Arg (z1/z4) + Arg (z2/z3) Equal
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0 votes0 answer142 views5 Years Ago
The Maximum Distance From The Origin Of Coordinate To Point Z Satisfying The Equation |z+1/z|=a Is
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Modified 5 Year Ago
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0 votes0 answer142 views5 Years Ago
Given That Equation Z^2 + (p+iq)z + R+ Is =0, Where P, Q, R,s Are Real And Non-Zero Has A Real Root , Then
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0 votes0 answer140 views5 Years Ago
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0 votes0 answer141 views5 Years Ago
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0 votes0 answer143 views5 Years Ago
If Z(1+a) = B +ic And A^2 +b^+ C^ = 1 , Then 1+iz/ 1-iz=
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0 votes0 answer137 views5 Years Ago
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0 votes0 answer149 views
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0 votes0 answer139 views5 Years Ago
Modified 5 Year Ago
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0 votes0 answer154 views5 Years Ago
The Point Representing The Complex Number Z, For Which |z-a|^2 + |z+a|^2= B^2 Lie On
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0 votes0 answer360 viewsYashwant 5 Years Ago
If |z1|=|z2| And Amp Z1 + Amp Z2 = 0 , Then
JEE DiscussionsModified 5 Year Ago Yashwant
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0 votes0 answer207 viewsSandeep 5 Years Ago
The Argument Of The Complex Number 13-5i/4-9i Is
JEE DiscussionsModified 5 Year Ago Sandeep
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0 votes0 answer114 views5 Years Ago
The Point In The Set {z E C : Arg [z-2/z-6i]=pi/2} (Where C Denotes The Set Of All Complex Number ) Lie On The Curve Which Is A
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0 votes0 answer125 views
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0 votes0 answer128 views5 Years Ago
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0 votes0 answer328 views5 Years Ago
If The Amplitude Of Z-2-3i Is Pi/4 , Then Locus Of Z=x+iy Is
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0 votes0 answer186 views5 Years Ago
The Multiplicative Inverse Of A Number Is The Number Itself , Then Its Initial Value Is
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0 votes0 answer151 viewsAnubhav 5 Years Ago
Modified 5 Year Ago Anubhav
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0 votes0 answer174 views5 Years Ago
If A = Cos (2pi/7)+ I Sin (2pi/7), Then The Quadratic Equation Whose Roots Are A =a+a^2+a^4 And B=a^3 +a^5+a^6 Is
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0 votes0 answer147 views5 Years Ago
If Z Iz And Z+ Iz Are The Vertices Of A Tringle Whose Area Is 2 Units , Then The Value Of |z|is
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0 votes0 answer226 views
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0 votes0 answer136 views5 Years Ago
If A = Cos A + I Sin A ,b= Cos B + I Sin B, C= Cos Y + I Sin Y And B/c + C/a + A/b= 1, Then Cos (b-y)+cos (y-a) +cos (a-b) Is Equal To
JEE DiscussionsModified 5 Year Ago