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5 Years Ago

When A Mass M Is Attached To A Spring, It Normally Extends By 0.2 M. The Mass M Is Given A Slight Additional Extension And Released, Then Its Time Period Will Be

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5 Years Ago

The Frequency Of Oscillation Of The Springs Shown In The Figure Will Be

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A Mass M Is Suspended By Two Springs Of Force Constants K1 And K2 Respectively As Shown In The Diagram. The Total Elongation (stretch) Of The Two Springs Is

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The Force Constants Of Two Springs Are K_1 And K_2 . Both Are Stretched Till Their Elastic Energies Are Equal. If The Stretching Forces Are F_1 And F_2 , Then

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A Body Of Mass 0.01 Kg Executes Simple Harmonic Motion (S.H.M.) About X = 0 Under The Influence Of A Force Shown Below : The Period Of The S.H.M. Is

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5 Years Ago

A Mass M Is Suspended Separately By Two Different Springs Of Spring Constant K1 And K2 Gives The Time-period T_1 And T_2 Respectively. If Same Mass M Is Connected By Both Springs As Shown In Figure

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5 Years Ago

One-fourth Length Of A Spring Of Force Constant K Is Cut Away. The Force Constant Of The Remaining Spring Will Be

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Sneha 5 Years Ago

Two Springs Of Force Constants K And 2K Are Connected To A Mass As Shown Below. The Frequency Of Oscillation Of The Mass Is

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5 Years Ago

A Mass M Is Suspended From A Spring Of Negligible Mass. The Spring Is Pulled A Little And Then Released So That The Mass Executes S.H.M. Of Time Period T. If The Mass Is Increased By M, The Time Perio

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5 Years Ago

A Particle At The End Of A Spring Executes Simple Harmonic Motion With A Period T1, While The Corresponding Period For Another Spring Is T2. If The Period Of Oscillation With The Two Springs In Series

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5 Years Ago

A Spring Has Length L And Spring Constant K. If Spring Is Divided In Two Equal Parts Then Spring Constant Is

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5 Years Ago

A Sphere Of Radius R Is Kept On A Concave Mirror Of Radius Of Curvature R. The Arrangement Is Kept On A Horizontal Table (the Surface Of Concave Mirror Is Frictionless And Sliding Not Rolling). If The

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5 Years Ago

Infinite Springs With Force Constants K, 2k, 4k And 8kâ€¦. Respectively Are Connected In Series. The Effective Force Constant Of The Spring Will Be

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5 Years Ago

Two Springs Are Connected To A Block Of Mass M Placed On A Frictionless Surface As Shown Below. If Both The Springs Have A Spring Constant K, The Frequency Of Oscillation Of The Block Is

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5 Years Ago

A Simple Pendulum Is Suspended From The Roof Of A Train. The Train Is Moving With Acceleration 49\,cm/ Sec ^2 . By What Angle To The Vertical, Its String Will Be Inclined

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5 Years Ago

A Simple Pendulum Consisting Of A Ball Of Mass M Is Tied To A Spring Of Length L Is Made To Swing On A Circular Arc Of Angle Q In A Vertical Plane. At The End Of This Arc, Another Ball Of Mass M Is Pl

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5 Years Ago

If The Length Of Secondâ€™s Pendulum Is Decreased By 2%, How Many Seconds It Will Lose Per Day

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5 Years Ago

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

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5 Years Ago

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

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5 Years Ago

The Period Of Oscillation Of A Simple Pendulum Of Length L Suspended From The Roof Of A Vehicle Which Moves Without Friction Down An Inclined Plane Of Inclination A, Is Given By

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5 Years Ago

The Period Of Oscillation Of A Simple Pendulum Of Constant Length At Earth Surface Is T. Its Period Inside A Mine Is

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5 Years Ago

A Hollow Sphere Is Filled With Water Through A Small Hole In It. It Is Then Hung By A Long Thread And Made To Oscillate. As The Water Slowly Flows Out Of The Hole At The Bottom, The Period Of Oscillat

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5 Years Ago

In Case Of A Simple Pendulum, Time Period Versus Length Is Depicted By

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5 Years Ago

A Simple Pendulum Of Length L Has A Brass Bob Attached At Its Lower End. Its Period Is T. If A Steel Bob Of Same Size, Having Density X Times That Of Brass, Replaces The Brass Bob And Its Length Is Ch

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5 Years Ago

A Chimpanzee Swinging On A Swing In A Sitting Position, Stands Up Suddenly, The Time Period Will

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5 Years Ago

Two Simple Pendulum Of Length 5 M And 20 M Respectively Are Given Small Linear Displacement In One Direction At The Same Time. They Will Again Be In The Phase When The Pendulum Of Shorter Length Has C

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Yug 5 Years Ago

The Bob Of A Simple Pendulum Executes Simple Harmonic Motion In Water With A Period T, While The Period Of Oscillation Of The Bob Is T0 In Air. Neglecting Frictional Force Of Water And Given That The

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5 Years Ago

In A Seconds Pendulum, Mass Of The Bob Is 30 Gm. If It Is Replaced By 90 Gm Mass. Then Its Time Period Will Be

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5 Years Ago

A Simple Pendulum Has Time Period T. The Bob Is Given Negative Charge And Surface Below It Is Given Positive Charge. The New Time Period Will Be

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5 Years Ago

A Block Of Wood Has Dimensions A, B And C. Its Relative Density Is D. It Is Floating In Water Such That The Side A Is Vertical. It Is Now Pushed Down Gently And Released. The Time Period Of Its S.H.M.

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JEE Discussions Simple Harmonic Motion Recent Questions

When A Mass M Is Attached To A Spring, It Normally Extends By 0.2 M. The Mass M Is Given A Slight Additional Extension And Released, Then Its Time Period Will Be

The Frequency Of Oscillation Of The Springs Shown In The Figure Will Be

A Mass M Is Suspended By Two Springs Of Force Constants K1 And K2 Respectively As Shown In The Diagram. The Total Elongation (stretch) Of The Two Springs Is

The Force Constants Of Two Springs Are K_1 And K_2 . Both Are Stretched Till Their Elastic Energies Are Equal. If The Stretching Forces Are F_1 And F_2 , Then

A Body Of Mass 0.01 Kg Executes Simple Harmonic Motion (S.H.M.) About X = 0 Under The Influence Of A Force Shown Below : The Period Of The S.H.M. Is

A Mass M Is Suspended Separately By Two Different Springs Of Spring Constant K1 And K2 Gives The Time-period T_1 And T_2 Respectively. If Same Mass M Is Connected By Both Springs As Shown In Figure

One-fourth Length Of A Spring Of Force Constant K Is Cut Away. The Force Constant Of The Remaining Spring Will Be

Two Springs Of Force Constants K And 2K Are Connected To A Mass As Shown Below. The Frequency Of Oscillation Of The Mass Is

A Mass M Is Suspended From A Spring Of Negligible Mass. The Spring Is Pulled A Little And Then Released So That The Mass Executes S.H.M. Of Time Period T. If The Mass Is Increased By M, The Time Perio

A Particle At The End Of A Spring Executes Simple Harmonic Motion With A Period T1, While The Corresponding Period For Another Spring Is T2. If The Period Of Oscillation With The Two Springs In Series

A Spring Has Length L And Spring Constant K. If Spring Is Divided In Two Equal Parts Then Spring Constant Is

A Sphere Of Radius R Is Kept On A Concave Mirror Of Radius Of Curvature R. The Arrangement Is Kept On A Horizontal Table (the Surface Of Concave Mirror Is Frictionless And Sliding Not Rolling). If The

Infinite Springs With Force Constants K, 2k, 4k And 8kâ€¦. Respectively Are Connected In Series. The Effective Force Constant Of The Spring Will Be

Two Springs Are Connected To A Block Of Mass M Placed On A Frictionless Surface As Shown Below. If Both The Springs Have A Spring Constant K, The Frequency Of Oscillation Of The Block Is

A Simple Pendulum Is Suspended From The Roof Of A Train. The Train Is Moving With Acceleration 49\,cm/ Sec ^2 . By What Angle To The Vertical, Its String Will Be Inclined

A Simple Pendulum Consisting Of A Ball Of Mass M Is Tied To A Spring Of Length L Is Made To Swing On A Circular Arc Of Angle Q In A Vertical Plane. At The End Of This Arc, Another Ball Of Mass M Is Pl

If The Length Of Secondâ€™s Pendulum Is Decreased By 2%, How Many Seconds It Will Lose Per Day

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

If The Length Of Simple Pendulum Is Increased By 300%, Then The Time Period Will Be Increased By

The Period Of Oscillation Of A Simple Pendulum Of Length L Suspended From The Roof Of A Vehicle Which Moves Without Friction Down An Inclined Plane Of Inclination A, Is Given By

The Period Of Oscillation Of A Simple Pendulum Of Constant Length At Earth Surface Is T. Its Period Inside A Mine Is

A Hollow Sphere Is Filled With Water Through A Small Hole In It. It Is Then Hung By A Long Thread And Made To Oscillate. As The Water Slowly Flows Out Of The Hole At The Bottom, The Period Of Oscillat

In Case Of A Simple Pendulum, Time Period Versus Length Is Depicted By

A Simple Pendulum Of Length L Has A Brass Bob Attached At Its Lower End. Its Period Is T. If A Steel Bob Of Same Size, Having Density X Times That Of Brass, Replaces The Brass Bob And Its Length Is Ch

A Chimpanzee Swinging On A Swing In A Sitting Position, Stands Up Suddenly, The Time Period Will

Two Simple Pendulum Of Length 5 M And 20 M Respectively Are Given Small Linear Displacement In One Direction At The Same Time. They Will Again Be In The Phase When The Pendulum Of Shorter Length Has C

The Bob Of A Simple Pendulum Executes Simple Harmonic Motion In Water With A Period T, While The Period Of Oscillation Of The Bob Is T0 In Air. Neglecting Frictional Force Of Water And Given That The

In A Seconds Pendulum, Mass Of The Bob Is 30 Gm. If It Is Replaced By 90 Gm Mass. Then Its Time Period Will Be

A Simple Pendulum Has Time Period T. The Bob Is Given Negative Charge And Surface Below It Is Given Positive Charge. The New Time Period Will Be

A Block Of Wood Has Dimensions A, B And C. Its Relative Density Is D. It Is Floating In Water Such That The Side A Is Vertical. It Is Now Pushed Down Gently And Released. The Time Period Of Its S.H.M.

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