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A+ib Greater Than C Id Can Be Explained Only When
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The Point Representing The Complex Number Z, For Which |z-a|^2 + |z+a|^2= B^2 Lie On
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If |z1|=|z2| And Amp Z1 + Amp Z2 = 0 , Then
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If (1-i/1+i)^100 =a+ib , Then
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The Argument Of The Complex Number 13-5i/4-9i Is
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The Point In The Set {z E C : Arg [z-2/z-6i]=pi/2} (Where C Denotes The Set Of All Complex Number ) Lie On The Curve Which Is A
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If M1,m2,m3 And M4 Respectively Denote The Moduli Of The Complex Number 1+4i, 3 +i, 1-i And 2-3i, Then The Correct One, Among The Following Is
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If The Amplitude Of Z-2-3i Is Pi/4 , Then Locus Of Z=x+iy Is
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The Valu Of (8)^1/3 Is
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The Multiplicative Inverse Of A Number Is The Number Itself , Then Its Initial Value Is
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(-1+ I Root 3 )^20 Is Equal To
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If X+1/x= Root3, Then X =
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If A = Cos (2pi/7)+ I Sin (2pi/7), Then The Quadratic Equation Whose Roots Are A =a+a^2+a^4 And B=a^3 +a^5+a^6 Is
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If Z Iz And Z+ Iz Are The Vertices Of A Tringle Whose Area Is 2 Units , Then The Value Of |z|is
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I Log (x-i/x+i) Is Equal To
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If A = Cos A + I Sin A ,b= Cos B + I Sin B, C= Cos Y + I Sin Y And B/c + C/a + A/b= 1, Then Cos (b-y)+cos (y-a) +cos (a-b) Is Equal To
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If Z=x + Iy And |z-2+i|=|z-3-i|, Then Locus Of Z Is |
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The Amplitude Of E^e-i Theetha Is Equal To
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If Xr = Cos (pi/2r)+i Sin (pi/2r), Then X1,x2, .....infinite Is
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Complex Number Z=(i-1)/cos (pi/3)+i Sin (pi/3) In Polar Form Is
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The Set C ={z|zz+az+az+b=0,b E R And B Less Than |a|^2}. Is
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The Equation |z-5i|/|z+5i|=12, Where Z = X+iy, Represents A/an
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If Z = (1+root3)/root3+i, Then (z)^100 Lies In
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The Imaginary Part Of I Is
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