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The Base BC Of A Trinagle ABC Is 6 Cm And
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If A + B + C = 180 Degree
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If In A Trinagle ABC , A/ Cos A = B/ Cos B, Then
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A^3 Cos (B - C) + B3 Cos (C - A) + C3 Cos (A - B) Is Equal To
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If The Angles Of A Triangle Are In The Ratio 1 : 1 : 4, Then The Ratio Of The Perimeter Of The Triangle To Its Largest Side Is
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In A ∆ABC, A,b, C Are The Sides Of The Triangle Opposite To The Angles A, B, C, Respectively. Then, The Value Of
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In A Triangle, The Lengths Of Two Larger Sides Are 10 Cm And 9 Cm. If The Angles Of The Triangle Are In AP, Then The Length Of The Third Side Is
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If Sin ^-1 + Sin ^-1y = Pie/2, Then Cos ^-1x + Cos ^-1y Is
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Tan ^-1 (x/root A^-x^) Is Equal To
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The Solution Of Tan^-1 2theta + Tan^-1 3theta = Pie/4 Is
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The Cos -1x = A, (0< X < 1) And Sin^ -1
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The Value Of Cot
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The Principal Value Of Sin^-1 {tan (-5pie/4)}
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If (tan^-1 X)^2 + (cot^-1 X )^2 = 5pie ^2/8 , Then X Is Equal To
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If0
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The Value Of Cos (2 Cos^-1 0.8) Is
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If Pie /2 < Sin ^-1x
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The Value Of X For Which Sin (cot ^-1 (1+ X)) + Cos (tan-1 X) Is
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If X Takes Negative Permissible Value, Then Sin^-1 X Is Equal To
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If Sin^-1 1/3 + Sin^-1 2/3 = Sin^-1 X, Then The Value Of X Is
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Value Of Tan -1 (sin2 Theta -1/cos2 Theta) Is
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If Sin^1 (x - X^2/2 + X^/4 - ...)
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The Number Of Real Solutions Of
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