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Dute To A Force Of (6l + 2j) N The Displacement Of A Body Is (3l - J) M, Then The Work Done Is
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Velocity And Acceleration Vectors Of Charged Particle Moving Perpendicular To The Direction Of A Magnetic Fieal At Given Instant Of Time Are
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If The Angle Between The Vectors A And B Is 0 Then The Value Of The Product (B * A) A Is Equal To
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A Particle Is Displaced From A Position (2j - J + K) To Another Position (3l + 2j - 2k) Under The Action Of The Force Of
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If The Scalar And Vector Products Of Two Vectors A And B Are Equal In Magnitude, Then The Angle Between The Two Vectors Is
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If A. B = La * Bl, Then Tan Will Be
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A Force F = 5i + 2j - 5k Acts On A Particle Whose Position Vector Is R = L - 2j + K. What Is The Torque About The Origin?
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Two Equal Vectors Have A Resultant Equal To Either Of Them, Then The Angle Between Them Will Be
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Two Equal Forces (P Each) Act At A Point Inclined To Each Other At An Angle Of 120°. The Magnitude Of Their Resultant Is
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Three Concurrent Coplanar Forces 1 N 2 N And 3 N Acting Along Different Directions On A Body
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If A = B + C And The Values Of A B And C Are 13 12 And 5 Respectively Then The Angle Between A And C Will Be
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If A = B + C And Have A B And C Scalar Magnitudes Of 5 4 And 3 Units Respectively Then The Angle Between A And C Is
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The Square Of Resultant Of Two Equal Forces Is Three Times Their Product. Angle Between The Forces Is
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How Many Minimum Number Of Coplanar Vectors Having Different Magnitudes Can Be Added To Give Zero Resultant?
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The Coordinates Of A Particle Moving In XY-plane At Any Instant Of Time T Are X = 4t^2, Y = 3t^2. The Speed Of The Particle At That Instant Is
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A Is A Vector With Magnitude A. Then The Unit Vector A In The Direction Of Vector A Is
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The Angle Between The Z -axis And The Vector (l + J + Root 2 K) Is The Angle Between The Z - Axis The Vector (l L + J + Root 2 K) Is
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