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Popular Questions
- the function f:R--{0}-->R, f(x)=1/x- 2/e^2x-1 can be made continuous at x=0 by defining f(0) as
- limX-->infinity logX^n -[x]/[x], nEN, ([x] denotes greatest integer less than or equal to x)
- Let f:R-R be a function such that
- Let f, g: R-R be two function defined by
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if f(x)={x, 0 less then equal to X less then equal to 1, 2x-1, 1
- the value of f(0), so that the function f(x)= root a^2-ax+x^2 - root a^2+a-x+x^2/root a+x - root a-x becomes continuous for all x,..
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if f(x)=cot^-1(3x-x^3/1-3x^2) and g(x)= cos^-1(1-x^2/1+x^2), then limX-->a f(x)-f(a)/g(x)-g(a), 0
- the composite mapping fog of the map f:R-->R, f(x)=sinX, g:R-->R, g(x)=x^2 is
- if g:[-2,2]-->R where g(x)= x^3 + tanX +[x^2+1/p] is a odd function then the value of parametric p is
- limX-->infinity (x+3/x+1)^x+1 =
- if f(x)=3x+10, g(x)=x^2-1, then (fog)^-1 is equal to
- 0 2f(x)-3f(2x)+f(4x)/x^2 is equal to"/>if f(x) is a Differentiable function and f"(0)=a, then limX-->0 2f(x)-3f(2x)+f(4x)/x^2 is equal to
- the function f(x)=1-sinX+cosX/1+sinX+cosX is not defined at x=pie. the value of f(pie), so that f(x) is continuous at x= pie, is
- in order that the function f(x)=(x+1)^cotX is continuous at x=0, f(0) must be defined as
- the function f(x)={x+2, 1 less then equal to X less then equal to 2, 4, x=2, 3x-2, x>2 is continuous at
- the set of points where f(x)=x/1+|x| is differentiable
- let f(x)= 1-tanX/4x-pie, x not equal to pie/4, xE[0,pie/2], if f(x) is continuous in [0,pie/2], then f(pie/4) is
- limX-->-2 sin-1(x+2)/x^2+2x is equal to
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the function f(x)={x, if 0 less then equal to X less then equal to 1 1, if 1
- the domain of the function f(x)= 1/log10 (1-x) + root x+2 is
- let f(x)={(x-1)sin 1/x-1 if x not equal to 1 0 if x=1. then which one of the following is true
- limX-->3 [x]=,(where[.]=greatest integer function)
- the function f(x)=sin|x| is
- the period of the function f(x)=|sinX|+|cosX| is
- if f(x)=x^2+1, then f^-1(17) and f^-1(-3) will be
- the function y=e^-|x| is
- if f(x)={1-|x|/1+x, x not equal to -1, 1, x=-1, then the value of f[2x] will be (where [.] shows the greatest integer function)
- if f(x)={x^2-9/x-3, if x not equal to 3, 2x+k, is continuous at x=3, then otherwise k=
- let f:(-1,1)-->R be a Differentiable function with f(0)=-1 and f(0)=1. let g(x)=[f(2f(x)+2)]^2. then g(0)=
- let f:R-->R be a positive increasing function with lomX-->infinity f(3x)/f(x)=1 then, limX-->infinity f(2x)/f(x)
- Let f:R-->R be a function defined by f(x)=min{x+1,|x|+1}. then which of the following is true
- the function f(x)={tanX/x , x not equal to 0. 1, x =0 is
- if f(x)={x,x greater than equal to 0 -x, x<0, then
- let f:(-1,1)-->B, be a function defined by f(x)=tan^-1 2x/1-x^2, then d is both one-one and onto when B is the interval
- let f(x)={sinX, forX greater then equal to 0 1-cosX, for X less then equal to 0 and g(x)=e^x. then (gof)(0) is
- the range of the function f(x)=^7-x px-3 is
- a Differentiable function f(x) is defined for all x>0 and satisfies f(x^3)=4x^4 for all x>0. the value of f(8) is
- consider f(x)={x^2/|x|, x not equal to 0 0, x=0
- a function f(x) is defined as follows for real X f(x)={1-x^2, for x<1 0, for x=1, then 1+x^2, for x>1
- Let f(x)
