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Let R1 Be A Relation Defined By R1 = {(a,b) | A≥b,a,b Set Membership R. Then R1 Is
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The Relation “less Than†In The Set Of Natural Numbers Is
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If N(A) = 3 And N(B) = 6 And A Subset B . Then The Number Of Elements In A Intersection B Is Equal To
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Let S = { 1,2,3,.......,100}. The Number Of Non-empty Subsets A Of S Such That The Product Of Elements In A Is Even Is
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In A Class Of 140 Students Numbered 1 To 140, All Even Numbered Students Opted Mathematics Course,
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Let A And B Be Two Non-empty Subsets Of A Set X Such That A Is Not A Subset Of B, Then
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In A Certain Town 25% Families Own A Phone And 15% Own A Car, 65% Families Own Neither A Phone Nor A Car
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With Reference To A Universal Set, The Inclusion Of A Subset In Another, Is Relation, Which Is
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If The Set A Contains 5 Elements, Then The Number Of Elements In The Power Set P(A) Is Equal To
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The Number Of Elements In The { (a,b) : 2a^2 +3b^2 = 35, A,b Sum Of Z} , Where Z Is The Set Of Integers, Is
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25 People For Programme A, 50 People For Programme B, People For Both. So, Number Of Employee Employed Only A Is
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If A = { 1, 2, 3, 4, 5 }, B = { 1, 4, 6 }, C = { 3, 4, 6 }, Then (A ⋃ B) ⋂ C Is
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Let S = {1,2,3,4}. The Total Number Of Unordered Pairs Of Disjoint Subsets Of S Is Equal To
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