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0 votes0 answer131 viewsAlan 4 Years Ago
Modified 4 Year Ago Alan
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0 votes0 answer127 viewsDavid 4 Years Ago
IF The Sum Of The Roots Of The Equation Ax^2 + Bx + C = 0 Be Equal To The Sum Of Their Squares, Then
JEE DiscussionsModified 4 Year Ago David
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0 votes0 answer125 viewsLavanya 4 Years Ago
If Alpha And Beta Are The Roots Of The Equation X^2 - A(x+1) - B = 0 Then ( Alpha + 1)( Beta + 1 ) =
JEE DiscussionsModified 4 Year Ago Lavanya
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0 votes0 answer199 viewsAbigail 4 Years Ago
If Alpha And Beta Are The Roots Of The Equation
JEE DiscussionsModified 4 Year Ago Abigail
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0 votes0 answer193 viewsConnor 4 Years Ago
If The Sum Of The Roots Of The Equation
JEE DiscussionsModified 4 Year Ago Connor
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0 votes0 answer128 viewsOlivia 4 Years Ago
If The Product Of The Roots Of The Equation (a + 1)x^2 + ( 2a +3 )x + ( 3a + 4 ) = 0, Then The Sum Of Roots Is
JEE DiscussionsModified 4 Year Ago Olivia
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0 votes0 answer209 views
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0 votes0 answer120 viewsAlan 4 Years Ago
If B^2 ≥ 4ac For The Equation Ax^4 + Bx^2 + C = 0, Then All The Roots Of The Equation Will Be Real, If
JEE DiscussionsModified 4 Year Ago Alan
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0 votes0 answer106 viewsConnor 4 Years Ago
If The Sum Of The Roots Of The Quadratic Equation Ax^2 + Bx + C = 0 Is Equal To The Sum Of The Squares Of Their Reciprocals, Then
JEE DiscussionsModified 4 Year Ago Connor
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0 votes0 answer109 viewsVanessa 4 Years Ago
Modified 4 Year Ago Vanessa
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0 votes0 answer126 viewsJoshua 4 Years Ago
If Alpha And Beta Are The Roots Of Ax^2 + 2bx + C = 0, Then
JEE DiscussionsModified 4 Year Ago Joshua
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0 votes0 answer124 viewsCarolyn 4 Years Ago
If The Roots Of Equation X^2 + Px + Q = 0 Differ By 1, Then
JEE DiscussionsModified 4 Year Ago Carolyn
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0 votes0 answer118 viewsAlexandra 4 Years Ago
If Alpha, Beta Are The Roots Of The Equation Lx^2 + Mx + N = 0, Then The Equation Whose Roots Are
JEE DiscussionsModified 4 Year Ago Alexandra
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0 votes0 answer310 viewsDominic 4 Years Ago
A Two Digit Number Is Four Times The Sum And Three Times The Product Of Its Digits. The Number Is
JEE DiscussionsModified 4 Year Ago Dominic
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0 votes0 answer197 views
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0 votes0 answer189 viewsHannah 4 Years Ago
The Sum Of The Roots Of A Equation Is 2 And Sum Of Their Cubes Is 98, Then The Equation Is
JEE DiscussionsModified 4 Year Ago Hannah
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0 votes0 answer129 viewsRuth 4 Years Ago
Modified 4 Year Ago Ruth
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0 votes0 answer137 viewsVirginia 4 Years Ago
If The Roots Of The Given Equation
JEE DiscussionsModified 4 Year Ago Virginia
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0 votes0 answer128 viewsFiona 4 Years Ago
If The Roots Of The Equation X^2 + 2mx + M^2 - 2m + 6 = 0 Are Same, Then The Value Of M Will Be
JEE DiscussionsModified 4 Year Ago Fiona
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0 votes0 answer122 viewsElla 4 Years Ago
Modified 4 Year Ago Ella
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0 votes0 answer126 viewsMegan 4 Years Ago
If Alpha, Beta Are The Roots Of Ax^2 + Bx + C = 0, Then The Equation Whose Roots Are 2 + Alpha, 2 + Beta Is
JEE DiscussionsModified 4 Year Ago Megan
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0 votes0 answer139 viewsDavid 4 Years Ago
If Alpha, Beta Are The Roots Of X^2 - 2x + 4 = 0, Then
JEE DiscussionsModified 4 Year Ago David
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0 votes0 answer122 viewsAnaisha 4 Years Ago
If The Roots Of Ax^2 + Bx + C = 0 Are Alpha, Beta And The Roots Of Ax^2 + Bx + C = 0 Are
JEE DiscussionsModified 4 Year Ago Anaisha
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0 votes0 answer215 viewsJennifer 4 Years Ago
If Alpha, Beta Are The Roots Of The Equation
JEE DiscussionsModified 4 Year Ago Jennifer
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0 votes0 answer268 views
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0 votes0 answer128 viewsEmily 4 Years Ago
Modified 4 Year Ago Emily
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0 votes0 answer84 viewsHarry 4 Years Ago
If One Of The Roots Of Equation X^2 + Ax + 3 = 0 Is 3 And One Of The Roots Of The Equation X^2 + Ax + B = 0 Is Three Times The Other Root,
JEE DiscussionsModified 4 Year Ago Harry
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0 votes0 answer92 viewsEmily 4 Years Ago
If The Ratio Of The Roots Of Ax^2 + 2bx + C = 0 Is Same As The Ratio Of The Roots Of Px^2 + 2qx + R = 0, Then
JEE DiscussionsModified 4 Year Ago Emily
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0 votes0 answer92 viewsJulian 4 Years Ago
If Alpha, Beta Are The Roots Of The Equation X^2 + Ax + B = 0, Then The Value Of Alpha^3 + Beta^3 Is Equal To
JEE DiscussionsModified 4 Year Ago Julian
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0 votes0 answer136 viewsBrandon 4 Years Ago
If The Product Of Roots Of The Equation, Mx^2 + 6x + (2m - 1) = 0 Is -1, Then The Value Of M Will Be
JEE DiscussionsModified 4 Year Ago Brandon