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Let Fk (x) = 1/k (sin ^k X + Cos ^k X) Where X
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In A Triangle PQR, If P + 4 X Cos Q = 6 And 4 Sin Q + 3 Cos P
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If A = Sin^2x + Cos^4x, Then For All Real X
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Let Cos (a+beta) = 4/5 And Let Sin (a - Beta)= 5/13, Where
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Let A And B Denote The Statement
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If 0 < X < Pie And Cos X + Sin X = 1/2, Then X Is
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The Number Of Solutions To Tan X + Sec X = 2 Cos X In
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The Sum Of All Values Of Theta E (0,pie/2) Satisfying
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The Sum Of All Values Of Theta E (0,pie/2) Satisfying
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If 0 < - X < Pie /2, Then Number Of Values Of X For Which
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The Value Of Cos^2 10 Degree Cos 50 Degrees +cos 50 Degree Is:
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If Sin^4 A + 4cos^4 Beta + 2 = 4 Root 2 A Cos Beta ;
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