(sin A /1 + cos A + 1 + cos A /sin A) (sin A / 1 - cos A - 1 - cos A /sin A)
2 sin A cos A + (cos A + sin A) square - (2 cos A + sin A) square
(cosec theta - sin theta) (sec theta - cos theta) = sin theta . cos theta
1 + tan cube theta / 1 tan theta + tan theta - sec square theta = 0
If A, B and C are interior angles of a triangle ABC
Express the trigonometric ratios sin A, tan A and sec A in terms of cot A
Prove the trigonometric identity
If sin theta - cos theta = 0,
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